COMPUTING

The Bipolar Junction Transistor as an AmplifierR CV SR BCI BBVBEICV CEEV CCandFigure 3.14. Circuit for Example 3.5Δi CΔv CEr out= ----------- = 10 5– Δv CEThis expression shows that there is a linear relationship between and V CE. The MATLABscript below performs all computations and plots versus . The plot is shown in Figure 3.15.vCE=1: 10; vA=80; iC1=0.8*10^(−3); r0=vA/iC1; iC=zeros(10,3);...iC(:,1)=vCE'; iC(:,2)=(vCE./r0)'; iC(:,3)=(iC1+vCE./r0)'; fprintf(' \n');...disp('vCE delta iC new iC');...disp('-------------------------');...fprintf('%2.0f \t %2.2e \t %2.2e\n',iC');...plot(vCE,iC(:,3)); xlabel('vCE (V)'); ylabel('iC (A)'); grid;...title('iC vs vCE for Example 3.5')vCE delta iC new iC-------------------------1 1.00e-005 8.10e-0042 2.00e-005 8.20e-0043 3.00e-005 8.30e-0044 4.00e-005 8.40e-0045 5.00e-005 8.50e-0046 6.00e-005 8.60e-0047 7.00e-005 8.70e-0048 8.00e-005 8.80e-0049 9.00e-005 8.90e-00410 1.00e-004 9.00e-004Generally, the i C versus v CE relation is non−linear. It is almost linear when a transistor operatesin the active region, and non−linear when it operates in the cutoff and saturation regions. Table3.2 shows the three modes of operation in a bipolar transistor and the forward or reverse−biasingof the emitter−base and collector−base junctions.I CV CEI CElectronic Devices and Amplifier Circuits with MATLAB Computing, Second EditionCopyright © Orchard Publications3−13