FINISHED_Final_Notebook_Jones

Use the space provided to write out the steps you take to solve different types of problems.
Use any additional space for notes. These 2 pages should be full when you turn in your notebook.
Steps to solve problems
1. Write out equation based on word problem.
Mole to Mole: Step 1/2:
___H 2 + ___O = ___H 2 O
2 2 2
2. Balance Equation
If you have 6 moles of H 2, how many moles of O will be needed to react?
2
Step 4:
6 moL H | 1 moL O
2
| 2 mol H
2
2
= 3 moL of O 2
3. Understand that in a balanced equation, all things are equivalent.
Thus, 1 moL of H would be equal to 1 moL of O or to 2 moL of H O
2 2 2
4. Write out "chart" beginning with the # of moL given (6 moL of H ) 2
5. Convert from mole to mole, because (using stoichiometry) 2 moles of H are
2
equal to 1 mole of O 2
Mole to Mass/Mass to Mole: How many moles of SO will react with 621g of O ?
Step 1: Write out equation based on word problem (already given)
2SO + O = 2SO
2 2 3
Step 2: Balance equation (already balanced)
3. Understand that in balanced equations, all
products/reactants are equivalent
2 2
Step 4: Write out chart beginning with MASS of moL given (621g of O ) 2
621g O | 1 moL O | 64g SO
2 2 2
| 32g O | 2 moL SO
2 2
=
39744
64
Step 5: Convert from grams to grams, as the molar mass of 1 moL of
O 2is 32g. Then, because 1 moL of O 2 is equivalent to 2 moLs of SO 2
convert from mole to mole.
How many grams of H O will be produced if 3.54 moles of S are produced?
2
Step 1: Write out equation based on word problem (already given)
2H S + SO = 3S + 2H O
2 2
2
Step 2: Balance equation (already balanced)
3. Understand that in balanced equations, all
products/reactants are equivalent
Step 4: Write out chart beginning with MOLES of S given (3.54 moL of S)
3.54 moL S | 2 moL H 2O | 18g H 2O
| 3 moL S | 1 mol H O
Step 5: Convert from moLs given to moLs in equation, using step 3.
Step 6: Determine molar mass of H 2 O to determine mass
of moLs of H 2 O
H | 2 x 1 = 2
O | 1 x 16 = 16
18g
2
= 621g of SO 2
= 127.44
3
Mass to Mass: How many grams of C H will be produced, if 85.8 grams of O are produced?
3 8 2
Step 1: Write out equation based on word problem (already given)
3CO + 4H O = C H + 5O
2 2 3 8 2
Step 2: Balance equations (already balanced)
3. Understand that in balanced equations, all
products/reactants are equivalent
Step 5: Determine molar mass of O 2
O | 2 x 16 = 32g
Step 4: Write out chart beginning with GRAMS of O given (85.8 grams O )
2 2
85.8g O 2| 1 moL O 2| 1 moL C 3H 8| 44g C 3H
8
| 32g O | 5 moL O | 1 moL C H
2
Step 7: Convert from grams to moles and then back to grams
Step 6: Determine molar mass of C H 3 8
C | 3 x 12 = 36
H | 8 x 1 = 8
44g
2
3 8
= 42.48 moL of H O 2
Step 7: Apply significant figures
=
42.5 moL of H O 2
= 3,775.2
160
= 23.595g of C H
3 8
Step 8: Apply significant figures
= 23.6 of C H 3 8
106