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2. What is the oxidation number of Na in Na2O?<br />

Since O = -2, the two Na must each be +1.<br />

3. What is the oxidation number of Cl in ClO¯?<br />

The O is -2, but since a -1 must be left over, then the Cl is +1.<br />

4. What is the oxidation number for each element in KMnO4?<br />

K = +1 because KCl exists. We know the Cl = -1 because HCl exists.<br />

O = -2 by definition<br />

Mn = +7. There are 4 oxygens for a total of -8, K is +1, so Mn must be the rest.<br />

5. What is the oxidation number of S in SO4 2¯<br />

O = -2. There are four oxygens for -8 total. Since -2 must be left over, the S must = +6.<br />

Please note that, if there is no charge indicated on a formula, the total charge is taken to be zero.<br />

Practice Problems<br />

Find oxidation numbers<br />

1. N in NO3¯<br />

2. C in CO3 2¯<br />

3. Cr in CrO4 2¯<br />

+5<br />

+4<br />

+6<br />

4. Cr in Cr2O7 2¯<br />

5. Fe in Fe2O3<br />

6. Pb in PbOH +<br />

+6<br />

+3<br />

+4<br />

7. V in VO2 +<br />

8. V in VO 2+<br />

+5<br />

4+<br />

9. Mn in MnO4¯<br />

+7<br />

10. Mn in MnO4 2¯<br />

+6<br />

Notes:<br />

O = 2- (unless w/ F [2+] or in a peroxide [1-])<br />

H = 1+ (unless with metal, then it is 1-)<br />

Any uncombined element = 0<br />

Monatomic ion = charge of ion<br />

Polyatomic ion = sum of oxidation #'s must equal charge<br />

Neutral compound = sum of oxidation #'s must equal 0<br />

Group 1 = oxidation # is 1+<br />

Group 2 = oxidation # is 2+<br />

Al = oxidation # is 3+<br />

Fluorine (F) = in a compound, oxidation # is always 1-<br />

Note: Most electronegative atom's oxidation # is the charge it would have if it were an ion.<br />

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