FINISHED_Final_Notebook_Jones
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2. What is the oxidation number of Na in Na2O?<br />
Since O = -2, the two Na must each be +1.<br />
3. What is the oxidation number of Cl in ClO¯?<br />
The O is -2, but since a -1 must be left over, then the Cl is +1.<br />
4. What is the oxidation number for each element in KMnO4?<br />
K = +1 because KCl exists. We know the Cl = -1 because HCl exists.<br />
O = -2 by definition<br />
Mn = +7. There are 4 oxygens for a total of -8, K is +1, so Mn must be the rest.<br />
5. What is the oxidation number of S in SO4 2¯<br />
O = -2. There are four oxygens for -8 total. Since -2 must be left over, the S must = +6.<br />
Please note that, if there is no charge indicated on a formula, the total charge is taken to be zero.<br />
Practice Problems<br />
Find oxidation numbers<br />
1. N in NO3¯<br />
2. C in CO3 2¯<br />
3. Cr in CrO4 2¯<br />
+5<br />
+4<br />
+6<br />
4. Cr in Cr2O7 2¯<br />
5. Fe in Fe2O3<br />
6. Pb in PbOH +<br />
+6<br />
+3<br />
+4<br />
7. V in VO2 +<br />
8. V in VO 2+<br />
+5<br />
4+<br />
9. Mn in MnO4¯<br />
+7<br />
10. Mn in MnO4 2¯<br />
+6<br />
Notes:<br />
O = 2- (unless w/ F [2+] or in a peroxide [1-])<br />
H = 1+ (unless with metal, then it is 1-)<br />
Any uncombined element = 0<br />
Monatomic ion = charge of ion<br />
Polyatomic ion = sum of oxidation #'s must equal charge<br />
Neutral compound = sum of oxidation #'s must equal 0<br />
Group 1 = oxidation # is 1+<br />
Group 2 = oxidation # is 2+<br />
Al = oxidation # is 3+<br />
Fluorine (F) = in a compound, oxidation # is always 1-<br />
Note: Most electronegative atom's oxidation # is the charge it would have if it were an ion.<br />
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