Mirath - The Laws of Islamic Inheritance

e multiplied into the Wifq of the third if there is a common divisor
between that and the first result (e.g. 6x3=18 (3 is the wifq of 9) this is
not divisible by the remaining number 4 but 2 is a common wifq. so
18x2=36). If there is not, then the result will be multiplied by the full
third number, and so on if there are yet more such heirs.
Note: If any of these numbers were Wifqs compared to their
allotment, then these Wifqs will be treated as the new full numbers
when compared to other heirs.
12 432
36
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4 Wives 9 Uterine Brothers 6 Brothers
1/4
1/3 Residue
3 4
5
108 144 180
27 x4 16 x9 30 x6
Note: It does not matter
with which pair of numbers
one starts, as the end result
will be the same in all cases.
e.g. 3x3x4, or 9x2x2, or 3x6x2
as long as one remembers to
use the full number of one.
6 and 9 have a common divisor i.e. 3,
thus the wifq of one (of 9 the wifq
is 3) is multiplied into 6 (the other
number) the result is 18, that will be
multiplied by the wifq of the
remaining 4 heirs (2). The result from
that i.e. 36 is made the multiplier.
(3) This is a situation when there are more than one type of heirs whose
allotments are indivisible in full numbers, and the numbers of heirs (or
their Wifqs) have no relationship to each other. In this situation the full
number of one of the inheritor groups will be multiplied with the full
number of the other(s), that is if the results bear no relationships with
the other number(s) of heirs.
If the result bears any common divisor with the remaining numbers
then the full amount of the result will be multiplied by the Wifq of the
remaining number to make the Ta]#|#.
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