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Vectors 403<br />

EXERCISE 5.8<br />

<br />

<br />

<br />

1. If r = xi yj zk<br />

r <br />

and r = | r | , show that (i) div<br />

3<br />

| r |<br />

<br />

= 0,<br />

<br />

(ii) div (grad r n ) = n (n + 1) r n – 2 (AMIETE, June 2010) (iii) div (r ) = 3 + r grad .<br />

<br />

2. Show that the <strong>vector</strong> V = ( x3 y) i ( y 3 z) j ( x 2 z)<br />

k is solenoidal.<br />

(R.G.P.V., Bhopal, Dec. 2003)<br />

3. Show that .( A) = .A + (.A)<br />

4. If , , z are cylindrical coordinates, show that grad (log ) and grad are solenoidal <strong>vector</strong>s.<br />

5. Obtain the expression for 2 f in spherical coordinates from their corresponding expression in<br />

orthogonal curvilinear coordinates.<br />

Prove the following:<br />

<br />

6. .( F) ( ). F ( . F )<br />

<br />

7. (a) .() = 2 <br />

(b)<br />

( A<br />

R) (2 n) A n( A. R)<br />

R <br />

, | |<br />

n n n 2 r R<br />

r r r<br />

8. div ( f g) – div (g f) = f 2 g – g 2 f<br />

5.31 CURL (U.P., I semester, Dec. 2006)<br />

The curl of a <strong>vector</strong> point function F is defined as below<br />

Curl F <br />

<br />

<br />

curl F = F<br />

<br />

= i j k ( F1 i F2 j F3<br />

k)<br />

x y z<br />

<br />

i j k<br />

=<br />

1 2 3<br />

is a <strong>vector</strong> quantity.<br />

5.32 PHYSICAL MEANING OF CURL<br />

<br />

<br />

<br />

( F F i F j F k)<br />

1 2 3<br />

F<br />

3 F2 <br />

F<br />

3 F1<br />

F2 F1<br />

i j k <br />

x y z <br />

y z<br />

<br />

x z<br />

<br />

x y<br />

<br />

F F F<br />

(M.D.U., Dec. 2009, U.P. I Semester, Winter 2009, 2000)<br />

We know that V r,<br />

where is the angular velocity, V is the linear velocity and <br />

r<br />

is the position <strong>vector</strong> of a point on the rotating body.<br />

<br />

Curl V 1 i 2 j 3<br />

k <br />

<br />

= V<br />

<br />

r x i y j zk <br />

<br />

<br />

= ( r ) = [( 1i 2 j 3<br />

k) ( xi y j zk)]<br />

=<br />

<br />

i j k<br />

<br />

= <br />

[( 2z 3y) i ( 1z 3x) j ( 1y 2x) k]<br />

<br />

1 2 3<br />

x y z<br />

<br />

x y z<br />

<br />

= i j k 2z 3y i 1z 3x j 1y 2x k<br />

<br />

[( ) ( ) ( ) ]

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