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Vectors 379<br />
EXERCISE 5.2<br />
1. Determine such that<br />
^ ^ ^ ^ ^ ^ ^ ^<br />
a i j k, b 2i 4 k, and c i j 3 k are coplanar. Ans. = 5/3<br />
2. Show that the four points<br />
^ ^ ^ ^ ^ ^ ^ ^ ^ ^ ^ ^<br />
6 i 3 j 2 k,3i 2 j 4 k,5i 7 j 3 k and 13 i 17 j k are coplanar.<br />
3. Find the constant a such that the <strong>vector</strong>s<br />
^ ^ ^ ^ ^ ^ ^ ^ ^<br />
2 i j k, i 2 j 3 k,and 3 i a j 5 k are coplanar. Ans. – 4<br />
4. Prove that four points<br />
^ ^ ^ ^ ^ ^ ^ ^ ^ ^ ^<br />
4 i 5 j k, ( j k), 3 i 9 j 4 k,4( i j k)<br />
are coplanar.<br />
<br />
5. If the <strong>vector</strong>s a, b and c are coplanar, show that<br />
<br />
a b c<br />
<br />
a . a a . b a . c<br />
<br />
b . a b . b b . c<br />
5.19 VECTOR PRODUCT OF THREE VECTORS (A.M.I.E.T.E., Summer, 2004, 2000)<br />
= 0<br />
Let a , b and c be three <strong>vector</strong>s then their <strong>vector</strong> product is written as a ( b × <br />
c ).<br />
Let<br />
<br />
^ ^ ^<br />
a = a i a j a k<br />
1 2 3 ,<br />
^ ^ ^<br />
b = b1 i b2 j b3 k,<br />
^ ^ ^<br />
c = c1 i c2 j c3<br />
k<br />
^ ^ ^ ^ ^ ^ ^ ^ ^<br />
( a1 i a2 j a3 k) ( b1 i b2 j b3 k) ( c1 i c2 j c3<br />
k)<br />
^ ^ ^ ^ ^ ^<br />
= a1 i a2 j a3 k bc 2 3 bc 3 2 i b3c1 b1c3 j bc 1 2<br />
bc 2 1 k<br />
a ( b c ) = <br />
=<br />
( ) [( ) ( ) ( ) ]<br />
^<br />
2 1 2 2 1 3 3 1 1 3 3 2 3 3 2 1 1 2<br />
2 1<br />
[ a ( b c b c ) a ( bc bc )] i [ a ( bc bc ) a ( b c b c )] j<br />
[ a ( b c b c ) a ( bc bc) k]<br />
1 3 1 1 3 2 2 3 3 2<br />
^ ^ ^ ^ ^ ^<br />
= ac 1 1 ac 2 2 ac 3 3 b1 i b2 j b3 k a1 b1 ab 2 2 ab 3 3 c1 i c2 j c3<br />
k<br />
= <br />
( )( ) ( )( )<br />
( a . c) b ( a . b) c .<br />
Ans.<br />
Example 8. Prove that :<br />
<br />
a ( b c) b ( c a) c ( a b ) 0 (Nagpur University, Winter 2008)<br />
Solution. Here, we have<br />
<br />
a ( b c) b ( c a) c ( a b )<br />
= <br />
[( a . c) b ( a . b) c] [( b . a) c ( b . c) a] [( c . b) b ( c . a) b]<br />
= <br />
[( b . a) c ( a . b) c] [( c . b) a ( b . c) a] [( a . c) b ( c . a) b]<br />
<br />
= [( a . b) c ( a . b) c] [( b . c) a ( b . c) a] [( c . a) b ( c . a) b]<br />
= 0 + 0 + 0 = 0 Proved.<br />
Example 9. Prove that :<br />
^ ^ ^ ^ ^ ^ <br />
i ( a i) j ( a j) k ( a k) 2 a (Nagpur University, Winter 2003)<br />
^ ^ ^<br />
Solution. Let a = a i a j a k<br />
1 2 3<br />
^<br />
^