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Vectors 421<br />
5.33 LINE INTEGRAL<br />
<br />
Let y,<br />
F ( x, z)<br />
be a <strong>vector</strong> function and a curve AB.<br />
Line integral of a <strong>vector</strong> function F along the curve AB is defined as integral of the component<br />
of F along the tangent to the curve AB.<br />
Component of F along a tangent PT at P<br />
= Dot product of F<br />
<br />
and unit <strong>vector</strong> along PT<br />
<br />
<br />
<br />
dr dr<br />
= F is aunit <strong>vector</strong> along tangent PT<br />
ds ds<br />
<br />
<br />
<br />
<br />
dr<br />
Line integral = F from A to B along the curve<br />
ds<br />
<br />
<br />
<br />
<br />
dr<br />
Line integral = F <br />
ds<br />
c<br />
ds<br />
=<br />
<br />
F<br />
<br />
dr<br />
<br />
<br />
c<br />
<br />
Note (1) Work. If F represents the variable force acting on a particle along arc AB, then the<br />
total work done =<br />
<br />
B<br />
F<br />
<br />
A<br />
<br />
dr<br />
(2) Circulation. If V represents the velocity of a liquid then<br />
V<br />
<br />
c<br />
<br />
dr is called the circulation<br />
of V round the closed curve c.<br />
If the circulation of V round every closed curve is zero then V is said to be irrotational there.<br />
(3) When the path of integration is a closed curve then notation of integration is in place<br />
<br />
of .<br />
22.If 2<br />
[(1 – x) (1 – 2x)] is equal to<br />
(i) 2 (ii) 3 (iii) 4 (iv) 6 (A.M.I.E.T.E., Dec. 2009) Ans. (iii)<br />
23.If R = xi + yj + zk and A <br />
is a constant <strong>vector</strong>, curl ( A R ) is equal to<br />
(i) R (ii) 2 R (iii) A (iv) 2 A (A.M.I.E.T.E., Dec. 2009) Ans. (iv)<br />
1<br />
24. If r is the distance of a point (x, y, z) from the origin, the value of the expression ˆj grad 2<br />
equals<br />
(i) 2 2 2<br />
3<br />
<br />
2 ˆ<br />
( x y z ) ( ˆjz kx)<br />
(ii)<br />
(iii) zero (iv)<br />
<br />
2<br />
Example 65. If a force F 2x yiˆ 3xyj<br />
ˆ displaces a particle in the xy-plane from (0, 0) to<br />
(1, 4) along a curve y = 4 x 2 . Find the work done.<br />
Solution. Work done = F <br />
. dr<br />
<br />
<br />
c r xiˆ yj ˆ<br />
<br />
<br />
2 <br />
<br />
=<br />
ˆ ˆ ˆ ˆ<br />
(2 x yi 3 xyj).( dx i dyj)<br />
dr dxiˆdyj<br />
ˆ<br />
<br />
=<br />
<br />
c<br />
c<br />
2<br />
(2 x y dx 3 xy dy)<br />
3<br />
<br />
2 2 2<br />
( x y z ) 2 ( ˆjz<br />
iz ˆ )<br />
3<br />
<br />
2 2 2 2 ˆ<br />
( x y z ) ( ˆjy<br />
kx)<br />
(AMIETE, Dec. 2010) Ans. (ii)