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Vectors 407<br />
=<br />
<br />
i j k<br />
<br />
x y z<br />
2 2<br />
y 2xy z<br />
<br />
= i(0) j(0) k(2y 2 y)<br />
= 0<br />
Hence, A is irrotational. To find the scalar potential function f.<br />
<br />
A<br />
= f<br />
df = f dx <br />
f dy <br />
f<br />
dz<br />
x y z<br />
<br />
= i j k f.<br />
dr<br />
x y z<br />
<br />
= Adr .<br />
f f f<br />
<br />
= i j k .( i dx jdy kdz)<br />
x y z<br />
<br />
= f.<br />
dr <br />
<br />
2 2<br />
= ( y i 2 xy j z k).( i dx jdy kdz)<br />
= y 2 dx + 2xy dy – z 2 dz = d (xy 2 ) – z 2 dz<br />
<br />
=<br />
f = d 2 2<br />
( xy ) z dz<br />
xy<br />
2<br />
3<br />
(A = f)<br />
z<br />
C<br />
Ans.<br />
3<br />
Example 47. A <strong>vector</strong> field is given by <br />
A = (x 2 + xy 2 ) i + (y 2 + x 2 y) j . Show that the field<br />
is irrotational and find the scalar potential.(Nagpur Univeristy, Summer 2003, Winter 2002)<br />
Solution. A is irrotational if curl A = 0<br />
<br />
i j k<br />
Curl A =<br />
Hence, A <br />
<br />
A<br />
<br />
<br />
A <br />
x y z<br />
2 2 2 2<br />
x xy y x y<br />
is irrotational. If is the scalar potential, then<br />
= grad <br />
d = dx <br />
dy <br />
dz<br />
x y z<br />
<br />
= i j k .( i dx jdy kdz)<br />
= grad . dr<br />
x y z<br />
<br />
<br />
0<br />
<br />
2 2 2 2<br />
<br />
= i(0 0) j(0 0) k(2xy 2 xy) 0<br />
[Total differential coefficient]<br />
= Adr . = [( x xy ) i ( y x y) j].( idx jdy kdz)<br />
= (x 2 + xy 2 ) dx + (y 2 + x 2 y) dy = x 2 dx + y 2 dy + (x dx)y 2 + (x 2 ) (y dy)<br />
=<br />
2 2 2 2<br />
xdx y dy [( xdx ) y ( x )( y dy )] =<br />
<br />
2 2<br />
3 3 2 2<br />
x y x y<br />
c Ans.<br />
3 3 2<br />
Example 48. Show that V( x, y, z) 2 x yzi ( x z 2 y)<br />
j x yk is irrotational and find a<br />
scalar function u(x, y, z) such that V <br />
= grad (u).<br />
Solution. V (x, y, z) =<br />
<br />
2 2<br />
2 xyzi ( x z 2 y)<br />
j x yk