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Vectors 407<br />

=<br />

<br />

i j k<br />

<br />

x y z<br />

2 2<br />

y 2xy z<br />

<br />

= i(0) j(0) k(2y 2 y)<br />

= 0<br />

Hence, A is irrotational. To find the scalar potential function f.<br />

<br />

A<br />

= f<br />

df = f dx <br />

f dy <br />

f<br />

dz<br />

x y z<br />

<br />

= i j k f.<br />

dr<br />

x y z<br />

<br />

= Adr .<br />

f f f<br />

<br />

= i j k .( i dx jdy kdz)<br />

x y z<br />

<br />

= f.<br />

dr <br />

<br />

2 2<br />

= ( y i 2 xy j z k).( i dx jdy kdz)<br />

= y 2 dx + 2xy dy – z 2 dz = d (xy 2 ) – z 2 dz<br />

<br />

=<br />

f = d 2 2<br />

( xy ) z dz<br />

xy<br />

2<br />

3<br />

(A = f)<br />

z<br />

C<br />

Ans.<br />

3<br />

Example 47. A <strong>vector</strong> field is given by <br />

A = (x 2 + xy 2 ) i + (y 2 + x 2 y) j . Show that the field<br />

is irrotational and find the scalar potential.(Nagpur Univeristy, Summer 2003, Winter 2002)<br />

Solution. A is irrotational if curl A = 0<br />

<br />

i j k<br />

Curl A =<br />

Hence, A <br />

<br />

A<br />

<br />

<br />

A <br />

x y z<br />

2 2 2 2<br />

x xy y x y<br />

is irrotational. If is the scalar potential, then<br />

= grad <br />

d = dx <br />

dy <br />

dz<br />

x y z<br />

<br />

= i j k .( i dx jdy kdz)<br />

= grad . dr<br />

x y z<br />

<br />

<br />

0<br />

<br />

2 2 2 2<br />

<br />

= i(0 0) j(0 0) k(2xy 2 xy) 0<br />

[Total differential coefficient]<br />

= Adr . = [( x xy ) i ( y x y) j].( idx jdy kdz)<br />

= (x 2 + xy 2 ) dx + (y 2 + x 2 y) dy = x 2 dx + y 2 dy + (x dx)y 2 + (x 2 ) (y dy)<br />

=<br />

2 2 2 2<br />

xdx y dy [( xdx ) y ( x )( y dy )] =<br />

<br />

2 2<br />

3 3 2 2<br />

x y x y<br />

c Ans.<br />

3 3 2<br />

Example 48. Show that V( x, y, z) 2 x yzi ( x z 2 y)<br />

j x yk is irrotational and find a<br />

scalar function u(x, y, z) such that V <br />

= grad (u).<br />

Solution. V (x, y, z) =<br />

<br />

2 2<br />

2 xyzi ( x z 2 y)<br />

j x yk

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