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Abel's theorem in problems and solutions - School of Mathematics

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82 Chapter 2<br />

286. Fix the value at a certa<strong>in</strong> po<strong>in</strong>t <strong>and</strong> def<strong>in</strong>e the<br />

values <strong>of</strong> function at the other po<strong>in</strong>ts <strong>of</strong> the plane (except the cut) by<br />

cont<strong>in</strong>uity along the curves start<strong>in</strong>g from <strong>and</strong> not <strong>in</strong>tersect<strong>in</strong>g the cut.<br />

Prove that the cont<strong>in</strong>uous s<strong>in</strong>gle-valued branches so obta<strong>in</strong>ed co<strong>in</strong>cide<br />

with the function (def<strong>in</strong>ed by the value at po<strong>in</strong>t<br />

It follows from the result <strong>of</strong> Problem 286 that, choos<strong>in</strong>g as <strong>in</strong>itial<br />

po<strong>in</strong>t different po<strong>in</strong>ts <strong>of</strong> the plane, one obta<strong>in</strong>s the same splitt<strong>in</strong>g <strong>of</strong> the<br />

Riemann surface <strong>in</strong>to s<strong>in</strong>gle-valued cont<strong>in</strong>uous branches. Therefore this<br />

splitt<strong>in</strong>g depends only on the way <strong>in</strong> which we have made the cut.<br />

287. Suppose that po<strong>in</strong>ts <strong>and</strong> do not lie on the cut <strong>and</strong> that the<br />

curve C, jo<strong>in</strong><strong>in</strong>g them, traverses the cut once (Figure 31). Choose a value<br />

<strong>and</strong> by cont<strong>in</strong>uity along C def<strong>in</strong>e the value Prove<br />

that values <strong>and</strong> correspond to different branches <strong>of</strong><br />

In this way, travers<strong>in</strong>g the cut, one moves from one branch to the<br />

other, i.e., the branches jo<strong>in</strong> each other exactly as we have put them<br />

together jo<strong>in</strong><strong>in</strong>g the sheets (Figure 29). One obta<strong>in</strong>s <strong>in</strong> this way the<br />

Riemann surface <strong>of</strong> the function<br />

We say that a certa<strong>in</strong> property is satisfied by any turn around a po<strong>in</strong>t<br />

if it is satisfied by a simple turn counterclockwise along all circles<br />

centred on <strong>and</strong> with sufficiently small radii 14 .<br />

288. Prove that by a turn around a po<strong>in</strong>t one rema<strong>in</strong>s on the same<br />

sheet <strong>of</strong> the Riemann surface <strong>of</strong> the function if <strong>and</strong> one moves<br />

onto the other sheet if<br />

The follow<strong>in</strong>g notion is very important <strong>in</strong> the sequel.<br />

DEFINITION. Po<strong>in</strong>ts, around which one may turn <strong>and</strong> move from one<br />

sheet to another (i.e., chang<strong>in</strong>g the value <strong>of</strong> the function) are called the<br />

branch po<strong>in</strong>ts <strong>of</strong> the given multi-valued function.<br />

The Riemann surface <strong>of</strong> the function can be represented by a<br />

scheme (Figure 32).<br />

This scheme shows that the Riemann surface <strong>of</strong> the function<br />

has two sheets, that the po<strong>in</strong>t is a branch po<strong>in</strong>t, <strong>and</strong> that by turn<strong>in</strong>g<br />

around the po<strong>in</strong>t one moves from one <strong>of</strong> the sheets to the other.<br />

Moreover, the arrow between the two sheets <strong>in</strong> correspondence with the<br />

po<strong>in</strong>t <strong>in</strong>dicates the passage from one sheet to the other not only<br />

by a turn around the po<strong>in</strong>t but also by cross<strong>in</strong>g a po<strong>in</strong>t <strong>of</strong> the<br />

14 More precisely, this means that there exists a real number such that the<br />

property mentioned is satisfied by any turn along any circle with centre <strong>and</strong> radius<br />

smaller than

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