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Los 500 mL se concentraron a 100 mL de ahí se le calcularon los gramos de<br />

taninos de la siguiente manera:<br />

ρ del extracto al1.5% = 1.004 g / mL<br />

ρ del extracto al 2.5% = 1.004 g / mL<br />

ρ del extracto al 3.5% = 1.004 g / mL<br />

V 1.5%<br />

V =<br />

m<br />

ρ<br />

0.45g<br />

=<br />

=<br />

1.004g<br />

mL<br />

( ) 0.4482mL<br />

V 2.5%<br />

0.75g<br />

1.004g<br />

mL<br />

( ) =<br />

= 0.7470mL<br />

V 3.5%<br />

1.05g<br />

1.004g<br />

mL<br />

( ) =<br />

= 1.0458mL<br />

Cantidad de tanino en preformulación al 1.5%<br />

0.041588g ______ 100mLextracto<br />

X ______ 0.4482mL<br />

X = 0.000186g de tanino en el extracto

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