Genel Bilgiler General Information - Stoewer-Getriebe.de
Genel Bilgiler General Information - Stoewer-Getriebe.de
Genel Bilgiler General Information - Stoewer-Getriebe.de
Erfolgreiche ePaper selbst erstellen
Machen Sie aus Ihren PDF Publikationen ein blätterbares Flipbook mit unserer einzigartigen Google optimierten e-Paper Software.
<strong>Genel</strong> <strong>Bilgiler</strong><br />
<strong>General</strong> <strong>Information</strong><br />
Einführung<br />
Eş<strong>de</strong>ğer güç hesabı<br />
Sabit <strong>de</strong>vir<strong>de</strong>, ancak <strong>de</strong>ğişken momentler<strong>de</strong><br />
(güçler<strong>de</strong>) çalışan redüktörler için eş<strong>de</strong>ğer tork<br />
altındaki, eş<strong>de</strong>ğer güç hesaplanabilir. Bu eş<strong>de</strong>ğer<br />
güç kullanılarak bilinen sabit güçteki redüktör<br />
seçim yöntemi kullanılarak seçim yapılabilir.<br />
Burada ağırlıklı torka göre eş<strong>de</strong>ğer anma torku<br />
belirlenmektedir. Hesaplanan bu güçte çalışan<br />
redüktör, teorik olarak, <strong>de</strong>ğişken yükler<strong>de</strong> çalışan<br />
redüktör ile aynı emniyet <strong>de</strong>ğerine ve ömre<br />
sahiptir.<br />
Bir çevrim boyunca oluşan <strong>de</strong>ğişken torklar, en<br />
yüksek torktan, en düşüğe doğru yatay zaman<br />
ekseni boyunca sıralanır (bakınız alttaki şekil). Bu<br />
şekile göre eş<strong>de</strong>ğer tork şu formül ile hesaplanır;<br />
Eğer T n <strong>de</strong>ğerleri (en düşük tork), T e ’nin 0,5 katının<br />
altında ise, bu tork dilimi yok sayılarak, işlem<br />
tekrarlanır;<br />
T<br />
e<br />
22<br />
T<br />
e<br />
=<br />
⎛ 6,<br />
6 6,<br />
6<br />
⎜<br />
Δt1<br />
⋅T1<br />
+ Δt2<br />
⋅T2<br />
+ ... + Δtn<br />
⋅T<br />
⎝<br />
t<br />
Eğer T<br />
n<br />
< Te ⋅ 0,<br />
5 ise<br />
⎛<br />
⎜ Δt1<br />
⋅T1<br />
= ⎜<br />
⎝<br />
6,<br />
6<br />
6,<br />
6<br />
+ Δt2<br />
⋅T2<br />
+ ... + Δt<br />
t −Δt<br />
6<br />
n<br />
⎜⎛<br />
1 ⎟⎞<br />
⎝ 6,<br />
6 ⎠<br />
Tüm T n <strong>de</strong>ğerleri T e ’nin 0,5 katının üzerin<strong>de</strong> ise,<br />
eş<strong>de</strong>ğer güç aşağıdaki gibi hesaplanır;<br />
P<br />
e<br />
= P<br />
N<br />
Eş<strong>de</strong>ğer gücün bulunmasından sonra P N <strong>de</strong>ğeri<br />
kullanılarak, bu katalogda verilen redüktör seçimi<br />
bölümün<strong>de</strong> anlatılan adımlar uygulanarak redüktör<br />
seçimi tamamlanır.<br />
n<br />
Te<br />
⋅n<br />
=<br />
9550<br />
, 6<br />
⎞<br />
⎟<br />
⎠<br />
⎜⎛<br />
1 ⎟⎞<br />
6,<br />
6 ⎞⎝<br />
6,<br />
6 ⎠<br />
n−1⋅Tn<br />
−1<br />
⎟<br />
⎟<br />
⎠<br />
T [Νm]<br />
T1<br />
Equivalent Power Rating<br />
The equivalent power by an equivalent constant<br />
torque can be calculated for gearboxes working<br />
in constant speed but variable torques (or<br />
powers). Using this equivalent power it is possible<br />
to make a gearbox selection according the usual<br />
gearbox selection way with constant torques. The<br />
equivalent torque will be <strong>de</strong>termined according<br />
the mean of dominating torques. The gearbox<br />
working in equivalent torque will theoretically have<br />
the same lifetime and safety compared to the<br />
variable torque one.<br />
For calculating the torques, the variable torques<br />
in a cycle must be sorted from the maximal to<br />
the minimal on a horizontal time line (Check the<br />
graphic below). According the graphic bellow the<br />
equivalent torque can be calculated by the<br />
following formula;<br />
T<br />
e<br />
=<br />
⎛ 6,<br />
6 6,<br />
6<br />
⎜<br />
Δt1<br />
⋅T1<br />
+ Δt2<br />
⋅T2<br />
+ ... + Δtn<br />
⋅T<br />
⎝<br />
t<br />
If T n (the lowest torque) is lower than 50% of T e,<br />
this torque part must be taken out from the torque<br />
graph and the calculation must be repeated;<br />
T<br />
e<br />
If T<br />
n<br />
< Te ⋅ 0,<br />
5 then<br />
⎛<br />
⎜ Δt1<br />
⋅T1<br />
= ⎜<br />
⎝<br />
6,<br />
6<br />
6,<br />
6<br />
+ Δt2<br />
⋅T2<br />
+ ... + Δt<br />
t −Δt<br />
6<br />
n<br />
⎜⎛<br />
1 ⎟⎞<br />
⎝ 6,<br />
6 ⎠<br />
If all T n values are higher then 50% of T e then the<br />
equivalent power can be calculated by the<br />
following formula;<br />
P<br />
e<br />
= P<br />
N<br />
After the equivalent power is <strong>de</strong>termined the<br />
selection of gearbox is ma<strong>de</strong> according the<br />
selection procedures given on the gearbox<br />
selection part in this catalogue.<br />
T2<br />
T3<br />
n<br />
Te<br />
⋅n<br />
=<br />
9550<br />
, 6<br />
⎞<br />
⎟<br />
⎠<br />
⎜⎛<br />
1 ⎟⎞<br />
6,<br />
6 ⎞⎝<br />
6,<br />
6 ⎠<br />
n−1⋅Tn<br />
−1<br />
Δt<br />
ΔtΔt ΔtΔtΔt<br />
t- Δ t<br />
T...<br />
t = ΣΔt = Δt + Δt<br />
+......+ Δt<br />
⎟<br />
⎟<br />
⎠<br />
Åquivalente Leistung<br />
Die mittlere Leistung bei äquivalentem<br />
Drehmoment für <strong>Getriebe</strong>n mit konstanter<br />
Drehzahl und variablen Leistungen kann berechnet<br />
wer<strong>de</strong>n. Mit dieser Leistung kann dass <strong>Getriebe</strong><br />
augelegt wer<strong>de</strong>n wie bei konstanten Leistung. Man<br />
bestimmt hiermit also die maßgeben<strong>de</strong> Belastung.<br />
Das hiermit ausgelegte <strong>Getriebe</strong> erreicht<br />
theoretisch die gleiche Lebensdauer und die<br />
gleiche Sicherheit.<br />
Für die äquivalente Drehmomentberechnung die<br />
einzelnen Drehmomentanteile müssen von<br />
größten zum kleinsten auf eine Zeitlinie geordnet<br />
wer<strong>de</strong>n (Ziehe unten angegebenes Bild). Die<br />
äquivalente Drehmoment wird nach folgen<strong>de</strong>r<br />
Formel berechnet;<br />
T<br />
e<br />
=<br />
⎛ 6,<br />
6 6,<br />
6<br />
⎜<br />
Δt1<br />
⋅T1<br />
+ Δt2<br />
⋅T2<br />
+ ... + Δtn<br />
⋅T<br />
⎝<br />
t<br />
Wenn T n (niedrigste Drehmoment) ist kleiner als<br />
50% von T e dann dieser Anteil muss rausgehalten<br />
wer<strong>de</strong>n und die Rechnung neu durchgeführt<br />
wer<strong>de</strong>n;<br />
T<br />
e<br />
T... Te<br />
Tn<br />
Wenn T<br />
n<br />
< Te ⋅ 0,<br />
5 dann<br />
⎛<br />
⎜ Δt1<br />
⋅T1<br />
= ⎜<br />
⎝<br />
6,<br />
6<br />
6,<br />
6<br />
+ Δt2<br />
⋅T2<br />
+ ... + Δt<br />
t −Δt<br />
6<br />
n<br />
⎜⎛<br />
1 ⎟⎞<br />
⎝ 6,<br />
6 ⎠<br />
Wenn alle Tn werte sind höher als 50% von Te<br />
dann die äquivalente Leistung wird nach folgen<strong>de</strong>r<br />
Formel berechnet;<br />
P<br />
e<br />
= P<br />
N<br />
Nach Bestimmung <strong>de</strong>r äquivalenter Leistung, die<br />
<strong>Getriebe</strong>auslegung erfolgt dann wie bei konstanter<br />
Leistung.<br />
0,5.Te<br />
t<br />
n<br />
Te<br />
⋅n<br />
=<br />
9550<br />
[Zaman/Time/Zeit]<br />
STÖWER ANTRIEBTECHNIK GmbH<br />
, 6<br />
⎞<br />
⎟<br />
⎠<br />
⎜⎛<br />
1 ⎟⎞<br />
6,<br />
6 ⎞⎝<br />
6,<br />
6 ⎠<br />
n−1⋅Tn<br />
−1<br />
⎟<br />
⎟<br />
⎠