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Semiparametric transformation models 143<br />

where the kernel k is given by k(t, u) = c(t∧u). Since this is the covariance function<br />

of a time transformed Brownian motion, we obtain a simpler equation. The solution<br />

to this Fredholm equation is<br />

(2.12)<br />

˜ ψ(t) =<br />

� τ<br />

0<br />

˜∆(t, u)˜ρ − ˙ G (u, θ0)EN(du),<br />

where ˜ ∆(t, u) = ˜ ∆(t, u,−1), and ˜ ∆(t, u, λ) is the resolvent corresponding to the<br />

kernel k. More generally, we consider the equation<br />

(2.13)<br />

Its solution is of the form<br />

˜ ψ(t) +<br />

� τ<br />

0<br />

˜ψ(t) = ˜η(t)−<br />

k(t, u) ˜ ψ(u)b(du) = ˜η(t).<br />

� τ<br />

0<br />

˜∆(t, u)b(du)˜η(u).<br />

To give the form of the ˜ ∆ function, note that the constant κθ0(τ) defined in (2.5)<br />

satisfies<br />

κ(τ) = κθ0(τ) =<br />

� τ<br />

0<br />

c(u)b(du).<br />

Proposition 2.3. Suppose that Assumptions 2.0(i) and (ii) are satisfied and<br />

v(u, θ0)�≡ 0, For j = 0,1, 2,3, n≥1 and s < t define interval functions Ψj(s, t) =<br />

� ∞<br />

m=0 Ψjm(s, t) as follows:<br />

Ψ00(s, t) = 1, Ψ20(s, t) = 1,<br />

� �<br />

Ψ0n(s, t) =<br />

Ψ0,n−1(s, u1−)c(du1)b(du2) n≥1,<br />

�<br />

s

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