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326 R. M. Mnatsakanov and F. H. Ruymgaart<br />

This yields for the bias (µ = x, σ 2 = x 2 /α)<br />

(3.8)<br />

� ∞<br />

fα(x)−f(x) = hα,x,1(y){f(y)−f(x)}du<br />

0<br />

� ∞<br />

= hα,x,1(y){f(x) + (y− x)f<br />

0<br />

′ (x)<br />

+ 1<br />

� ∞<br />

(y− x)<br />

2 0<br />

2 {f ′′ (˜y)−f(x)}dy<br />

= 1<br />

� ∞<br />

(y− x)<br />

2 0<br />

2 hα,x,1(y)f ′′ (x)du<br />

+ 1<br />

� ∞<br />

2 0<br />

= 1 x<br />

2<br />

2<br />

α f ′′ � �<br />

1<br />

(x) + o , as α→∞.<br />

α<br />

For the variance we have<br />

(y− x) 2 hα,x,1(y){f ′′ (˜y)−f ′′ (x)}dy<br />

(3.9) Var � f ∗ α(x) = 1<br />

n VarMi = 1<br />

n {E M2 i− f 2 α(x)}.<br />

Applying (3.6) for k = 2 yields<br />

(3.10)<br />

E M 2 i = W α2<br />

x 2<br />

∼ α2<br />

x2 (2α−3)!<br />

{(α−1)!} 2<br />

1<br />

22α−2 � ∞<br />

hα,x,2(u)f(u)du<br />

0<br />

e−(2α−3) {(2α−3)} (2α−3)+1/2<br />

e−2(α−1) {(α−1)} 2(α−1)+1<br />

1<br />

22(α−1) W<br />

√<br />

2π<br />

� ∞<br />

× hα,x,2(u)f(u)du =<br />

0<br />

W<br />

2 √ √<br />

α<br />

π x2 � ∞<br />

hα,x,2(u)f(u)du<br />

0<br />

= W<br />

2 √ √<br />

α<br />

W<br />

π x2{f(x) + o(1)} =<br />

2 √ √<br />

α<br />

π x2 f(x) + o(√α) as α→∞. Now inserting this in (3.9) we obtain<br />

(3.11)<br />

Var � f ∗ α(x) = 1<br />

�<br />

W<br />

n 2 √ π<br />

= W√ α<br />

2n √ π<br />

Finally, this leads to the MSE of � f ∗ α(x):<br />

(3.12) MSE{ � f ∗ α(x)} = W√ α<br />

2n √ π<br />

For optimal rate we may take<br />

√<br />

α<br />

x2 f(x) + o(√α)− �√ �<br />

f(x) α<br />

+ o .<br />

x2 n<br />

�<br />

f(x) + O<br />

f(x) 1 x<br />

+<br />

x2 4<br />

4<br />

α2{f ′′ (x)} 2 + o<br />

(3.13) α = αn∼ n 2/5 ,<br />

�√ �<br />

α<br />

n<br />

� ��2 1<br />

�<br />

α<br />

�<br />

1<br />

+ o<br />

α2 �<br />

.<br />

assuming that n is such that αn is an integer. By substitution (3.13) in (3.12) we<br />

find (3.5).

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