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Quantum Information Theory with Gaussian Systems

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= − 1<br />

2<br />

2Nf <br />

i,j=1<br />

where M ′ =<br />

M ′ i,j (α′ − β ′ )i (α ′ − β ′ )j ,<br />

Nf<br />

n=1<br />

2 log<br />

<br />

γn − 1<br />

.<br />

γn + 1<br />

5.2 Security estimation<br />

The last identity is due to the fact that T(α), T(β) and T(0) all possess the same<br />

covariance matrix γ = 2Nf + σ T G−1 σ by (5.2) and that T(0) is centered around<br />

zero, i.e. tr[T(0)R ′ k ] = 0 for all field operators R′ k <strong>with</strong> k = 1, . . .,2Nf. Recall from<br />

Section 2.2.2 that the prime indicates the basis in which the covariance matrix is<br />

diagonal. For isotropic, uncorrelated <strong>Gaussian</strong> noise <strong>with</strong> G = 2Nf/g this yields<br />

γ = (1 + g) 2Nf <strong>with</strong> symplectic eigenvalues γn = 1 + g and thus<br />

S T(α) T(β) = log(1 + 2/g) |α − β| 2 /2 ≤ 4 log(1 + 2/g)NfEmax .<br />

Combining this estimate <strong>with</strong> (5.6) yields the bound<br />

<br />

T(α) − T(β) 1 ≤ 2 2 log(1 + 2/g)NfEmax , (5.7)<br />

which proves the functioning of the continuous randomization in the first place,<br />

since both output states can be made arbitrarily indistinguishable from each other<br />

by choosing g large enough.<br />

As a first step towards the discrete protocol, we approximate the ideal randomization<br />

(5.1) by the cutoff integral (5.3). To estimate the error T [](α) − T(α) 1 we<br />

compare both channels <strong>with</strong> the nonnormalized, completely positive map c [ ]<br />

c T [](α):<br />

<br />

T[](α) − T(α) 1 ≤ T[](α) − c [ ]<br />

c T [](α) 1 + c []<br />

c T [ ](α) − T(α) 1 . (5.8)<br />

Both terms will be estimated by the same bound for the difference between the full<br />

and the cutoff classical integral:<br />

<br />

T[ ](α) − c [ ]<br />

c T [ ](α) = 1 1<br />

c |c − c [ ]| T[](α) <br />

1<br />

= 1<br />

<br />

<br />

dξ e<br />

c<br />

−ξT <br />

·G·ξ/4<br />

− dξ e −ξT <br />

·G·ξ/4<br />

<br />

<br />

c []<br />

c T [](α) − T(α) 1 =<br />

since T[](α) = 1 1<br />

= 1<br />

<br />

c<br />

<br />

<br />

1<br />

c<br />

= 1<br />

c<br />

|ξ|≥a<br />

<br />

|ξ|≥a<br />

<br />

|ξ|≥a<br />

|ξ|≤a<br />

dξ e −ξT ·G·ξ/4 , (5.9a)<br />

<br />

<br />

dξ e −ξT ·G·ξ/4<br />

Wξ |α〉〈α|W ∗ ξ <br />

1<br />

dξ e −ξT ·G·ξ/4<br />

since Wξ |α〉〈α|W ∗ <br />

<br />

ξ = 1.<br />

1<br />

(5.9b)<br />

107

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