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Quantum Information Theory with Gaussian Systems

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4 <strong>Gaussian</strong> quantum cellular automata<br />

−π<br />

−π/2<br />

1.0<br />

0.5<br />

α(k)<br />

Figure 4.3:<br />

Plot of α(k) = arccos cosφ +f cos(k)sin φ according to Eq.(4.19), for f = 0.4<br />

and φ = π<br />

4 .<br />

states, we concentrate on the nondegenerate case of small couplings |f| < tan(φ/2) <br />

or |f| < cot(φ/2) . The above relations between f and the eigenvalues are illustrated<br />

in Fig. 4.2; for a plot of the resulting α(k) see Fig. 4.3.<br />

We will consider below the time evolution of the initial state, show that it converges<br />

and characterize the possible limit states. The following arguments make use of the<br />

projectors onto the eigenspaces of ˆ Γ, which are provided by<br />

Lemma 4.6:<br />

If ˆ Γ(k) has nondegenerate, complex eigenvalues e ±iα(k) <strong>with</strong> α(k) ∈ (0, π), the<br />

(nonorthogonal) projectors Pk and Pk onto its eigenspaces in a decomposition<br />

are given by<br />

Pk = 1<br />

2<br />

and Pk as the complex conjugate of Pk.<br />

π/2<br />

ˆΓ(k) = e iα(k) Pk + e −iα(k) Pk<br />

k<br />

π<br />

<br />

i + 2 cosα(k) − Γ(k) ˆ −1<br />

sin α(k)<br />

(4.21)<br />

(4.22)<br />

Proof: The operators Pk and Pk = − Pk are projectors onto the disjoint eigenspaces<br />

of ˆ Γ(k). 8 Since Pk + Pk = , the real and imaginary parts of both projectors<br />

are connected via Re Pk = − Re Pk and ImPk = − ImPk. Writing the above<br />

decomposition (4.21) in terms of Re Pk and ImPk yields<br />

ˆΓ(k) = cosα(k) − 2 sin α(k) Im Pk + i sinα(k)(2 RePk − ). (4.23)<br />

By (4.18), ˆ Γ(k) has to be real-valued. Hence the last term of (4.23) has to vanish<br />

and we immediately obtain RePk = /2. Note that we excluded the degenerate<br />

8 Proof of this statement: If ψ− is the eigenvector of ˆ Γ(k) to eigenvalue e−iα(k) , then e−iα(k) ψ− =<br />

ˆΓ(k) · ψ− = ` eiα(k) Pk + e−iα(k) ( − Pk) ´ · ψ−, which implies Pk · ψ− = 0 and Pk · ψ− = ψ−.<br />

Similarly, Pk · ψ+ = ψ+ and Pk · ψ+ = 0 for the eigenvector ψ+ to eigenvalue eiα(k) . Since ˆ Γ(k)<br />

has determinant 1 and thus full rank, the eigenvectors are linearly independent and span the<br />

whole spaceÊ2 . Hence 0 = Pk ·Pk = Pk ·( −Pk) = Pk −P 2 k or P2 k = Pk , i.e. Pk is a projector.<br />

The same holds for Pk.<br />

84

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