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Random Processes in Hyperbolic Spaces Hyperbolic Brownian ...

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37 <strong>Hyperbolic</strong> <strong>Brownian</strong> Motion<br />

(x, y) ∈ H 2 may be realized as the solution of the stochastic differential equations<br />

⎧<br />

⎨dX(t)<br />

= Y (t)dB1(t) − νY (t)dt,<br />

⎩dY<br />

(t) = Y (t)dB2(t) − µ − 1<br />

<br />

Y (t)dt,<br />

where B1(t) and B2(t) are two <strong>in</strong>dependent one-dimensional <strong>Brownian</strong> motions. Z(t) is represented<br />

as follows ⎧<br />

⎨X(t)<br />

= x + y<br />

⎩<br />

t<br />

0 exp{Bµ 2 (s)} dBν 1 (s),<br />

Y (t) = y exp{B µ<br />

2 (t)},<br />

where B ν 1 (t) = B1(t)−νt and B µ<br />

2 (t) = B2(t)−µt. S<strong>in</strong>ce µ is assumed to be positive, Y (t) converges<br />

to 0 as t tends to ∞. It is possible to show that the distribution of the horizontal component X(t)<br />

converges weakly as t tends to <strong>in</strong>f<strong>in</strong>ity to a given limit<strong>in</strong>g distribution.<br />

Let ha = {z ∈ H2 : Im{z} = a}, with 0 ≤ a < y, be the horocycle through ∞. If a = 0 we<br />

have that h0 is the boundary of the hyperbolic half plane H2. The hitt<strong>in</strong>g distribution on ha, with<br />

a > 0, of the diffusion process associated to L is given by the law of the random variable<br />

τa<br />

Xτa = x + y exp{B<br />

0<br />

µ<br />

2 (s)} dBν 1 (s)<br />

where τa = <strong>in</strong>f{t ≥ 0 : Y (t) = a} is the first hitt<strong>in</strong>g time on ha. With a slight abuse of term<strong>in</strong>ology<br />

the law of the random variable<br />

is the hitt<strong>in</strong>g distribution on h0.<br />

Hitt<strong>in</strong>g distribution on h0<br />

X∞ = x + y<br />

∞<br />

0<br />

exp{B µ<br />

2 (s)} dBν 1 (s)<br />

Let pz(ξ) be the density of the hitt<strong>in</strong>g distribution on h0 for the process associated to the operator<br />

L and start<strong>in</strong>g at z = (x, y). We po<strong>in</strong>t out that pz(ξ) is the Poisson kernel of L <strong>in</strong> the doma<strong>in</strong> H 2<br />

and satisfies the follow<strong>in</strong>g conditions:<br />

⎧<br />

Lpz(ξ) = 0, ∀ξ ∈ h0,<br />

⎪⎨ pz(ξ) > 0, ∀ξ ∈ h0,<br />

∞<br />

−∞<br />

⎪⎩<br />

pz(ξ)dξ = 1,<br />

limy→0 + pz(ξ) = 0, if ξ = x.<br />

S<strong>in</strong>ce L is <strong>in</strong>variant under the action of the map z → az + b then so is pz(ξ)dξ on R. That is<br />

pz(ξ) dξ = paz+b(aξ + b) d(aξ + b) = a paz+b(aξ + b) dξ.<br />

Sett<strong>in</strong>g a = 1 x<br />

y , b = − y and f(x) = pi(x) we have<br />

pz(ξ) = px+iy(ξ) = 1<br />

y pi<br />

<br />

ξ − x<br />

y<br />

2<br />

= 1<br />

y f<br />

<br />

ξ − x<br />

y<br />

(3.28)<br />

(3.29)

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