Download - NASA
Download - NASA
Download - NASA
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Aircraft 61<br />
where Δz F = z F − z F cg. In hover and low speed, the download is calculated: F I z = k T (C IF F F ), the<br />
downward component of the aerodynamic force in inertial axes. <strong>Download</strong> can be expressed as a fraction<br />
of the total rotor vertical force, or as a fraction of gross weight. The aerodynamic model also calculates<br />
the interference velocities caused by this component at all other components: v F int = CFB v B int.<br />
Equations for the aerodynamics models are defined for all angles in radians. Input values of angles<br />
will, however, be in degrees.<br />
The aircraft neutral point is calculated from the airframe aerodynamics with all controls set to zero.<br />
The neutral point is here defined as the longitudinal position about which the derivative of the pitch<br />
moment with lift is zero. Hence SLna = SLcg − ΔM/ΔL, with the change in lift and moment calculated<br />
from the loads at angles of attack of 0 and 5 degree.<br />
7–8 Trailing-Edge Flaps<br />
The lifting surfaces have controls in the form of trailing-edge flaps: flap, flaperon, and aileron for<br />
wings; elevator or rudder for tails. The aerodynamic loads generated by flap deflection δf (radians) are<br />
estimated based on two-dimensional aerodynamic data (as summarized in refs. 1 and 2). Let ℓf = cf /c<br />
be the ratio of the flap chord to the wing chord. The lift coefficient is cℓ = cℓα(α + τηδf ), where<br />
η ∼ = 0.85 − 0.43δf is an empirical correction for viscous effects (ref. 1, eq. 3.54 and fig. 3.36). Thin<br />
airfoil theory gives<br />
τ =1− θf − sin θf<br />
π<br />
∼=<br />
<br />
sin( π<br />
2 ℓf<br />
n )<br />
with θf = cos −1 (2ℓf − 1) (ref. 1, eq. 3.56 and fig. 3.35; ref. 2, eq. 5.40). The last expression is an<br />
approximation that is a good fit to the thin airfoil theory result for n = 1/2, and a good approximation<br />
including the effects of real flow for n = 2/3 (ref. 2, fig. 5.18); the last expression with n = 2/3 is used<br />
here. The increase of maximum lift coefficient caused by flap deflection is less than the increase in lift<br />
coefficient, so the stall angle-of-attack is decreased. Approximately<br />
Δcℓmax ∼= (1 − ℓf )(1+ℓf − 5ℓ 2 f +3ℓ 3 f )<br />
Δcℓ<br />
(ref. 1, fig. 3.37). Thin airfoil theory gives the moment-coefficient increment about the quarter chord:<br />
<br />
<br />
<br />
Δcm = −0.85 (1 − ℓf ) sin θf δf = −0.85 (1 − ℓf )2 (1 − ℓf )ℓf δf<br />
(ref. 1, eq. 3.57; ref. 2, eq. 5.41); with the factor of 0.85 accounting for real flow effects (ref. 2, fig. 5.19).<br />
The drag increment is estimated using<br />
ΔCD =0.9 ℓ 1.38<br />
f<br />
Sf<br />
S sin2 δf<br />
for slotted flaps (ref. 1, eq. 3.51). In summary, the section load increments are:<br />
Δcℓ = cℓα<br />
Δcℓmax = Xf Δcℓ<br />
cf<br />
c Lf ηf δf<br />
Δcm = cf<br />
c Mf δf<br />
The decrease in angle-of-attack for maximum lift is<br />
Δαmax = − Δcℓ − Δcℓmax<br />
= −(1 − Xf ) Δcℓ<br />
cℓα<br />
cℓα