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1,2,3-Dithiazolyl and 1,2,35-Dithiadiazolyl Radicals as Spin-Bearing ...

1,2,3-Dithiazolyl and 1,2,35-Dithiadiazolyl Radicals as Spin-Bearing ...

1,2,3-Dithiazolyl and 1,2,35-Dithiadiazolyl Radicals as Spin-Bearing ...

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ing w<strong>as</strong> formed. One of the nitrogen atoms in this second TDA moiety actually formed a<br />

third bond to bridge two 6-membered carbon rings. A sulfur atom positioned ortho to the<br />

bridging nitrogen atom also formed a bridging interaction with the other ring.<br />

This crystal structure is shown in Figure 5-6. The R value for this compound w<strong>as</strong> found<br />

to be 6.01% <strong>and</strong> therefore the identities of the chlorine atoms on the cation are less in<br />

question. Important crystallographic parameters for these two compounds are outlined in<br />

table 5-1.<br />

5.2.5 EPR Spectroscopy<br />

Despite not obtaining a purified product we were able to obtain an EPR spectrum of<br />

what is believed to be V-1. The spectra obtained from full scale reductions of any of the<br />

precursor salts were usually low intensity <strong>and</strong> poorly defined, especially from reactions<br />

using V-3 or V-4. Higher quality data were obtained from performing the reduction in<br />

situ, using an EPR tube with a wide reservoir outside of the narrow quartz tube which is<br />

inserted into the instrument. The spectrum shown in Figure 5-7 w<strong>as</strong> obtained from V-3,<br />

using triphenyl antimony <strong>as</strong> the reducing agent in methylene chloride which w<strong>as</strong> added<br />

under argon before the cell w<strong>as</strong> sealed with a rotoflo to ensure an inert atmosphere. The<br />

portion of the signal on the far right of the spectrum is not <strong>as</strong> well resolved <strong>as</strong> the portion<br />

on the left, arising from slow tumbling of the radical in solution. The experimental<br />

spectrum appears at the top <strong>and</strong> it can be seen that the primary signal h<strong>as</strong> been split into<br />

three separate lines <strong>and</strong> each of the these have been split further for a total of 7 lines. As<br />

14 N h<strong>as</strong> a nuclear spin of 1, the three primary lines of the spectrum are from strong<br />

coupling to one of the nitrogen atoms in the molecule. This is most likely the nitrogen<br />

148

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