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1,2,3-Dithiazolyl and 1,2,35-Dithiadiazolyl Radicals as Spin-Bearing ...

1,2,3-Dithiazolyl and 1,2,35-Dithiadiazolyl Radicals as Spin-Bearing ...

1,2,3-Dithiazolyl and 1,2,35-Dithiadiazolyl Radicals as Spin-Bearing ...

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equired to obtain a decent agreement with the experimental spectrum. This nitrogen<br />

atom w<strong>as</strong> found to have a coupling constant a factor of 10 lower than the primary<br />

splitting factor at 0.653 G. 1 H h<strong>as</strong> a nuclear spin I = 1/2 <strong>and</strong> w<strong>as</strong> <strong>as</strong>signed a coupling<br />

constant with the value 0.473 G <strong>and</strong> the chlorine atom, the two major isotopes for which<br />

have a spin of I = 3/2, w<strong>as</strong> <strong>as</strong>signed with a value of 0.705 G. The g value w<strong>as</strong> found to be<br />

2.00796, higher than the me<strong>as</strong>ured value for a free electron at 2.0032. 7 An agreement<br />

factor of 93.3% w<strong>as</strong> obtained using a line width of 0.22. There are yet features that are<br />

not present in the simulation such <strong>as</strong> a shoulder on the central peak of each of the first<br />

two multiplets, but it may be impossible to simulate these given the anisotropy of the<br />

spectrum. It should be noted that the substantial anisotropy seen in the experimental<br />

spectrum implies slow tumbling which is characteristic of a molecule much larger than<br />

the expected structure of V-1.<br />

5.2.6 Conclusions <strong>and</strong> Future Work<br />

Calculations were carried out for the radical V-1 <strong>and</strong> the SOMO is shown in Figure<br />

5-8. There are substantial coefficients on the chlorine atom <strong>as</strong> well <strong>as</strong> the halide-bearing<br />

carbon <strong>and</strong> the Mulliken atomic spin densities of 2% <strong>and</strong> 23% respectively confirm that<br />

there is a substantial amount of the radical character at these atoms. No evidence h<strong>as</strong> been<br />

found suggesting that a carbon-carbon bond is being formed between two of these<br />

molecules to destroy the radical, however the calculations suggest that it may be a<br />

possibility. While there is a small amount of spin density expected to be on the chlorinebearing<br />

carbon atom, the steric bulkiness of the halogen may be enough to prevent the<br />

150

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