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The QCD Quark Propagator in Coulomb Gauge and - Institut für Physik

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Chapter 6. Nucleon Form Factors <strong>in</strong> a Covariant Diquark-<strong>Quark</strong> model 61<br />

where (I D ) rs = δ rs , ˆl 2 = 1, ˆP 2 = −1. In the nucleon rest frame, s 1,2 describe, respectively,<br />

the upper, lower component of the bound-state nucleon’s sp<strong>in</strong>or. Plac<strong>in</strong>g the same<br />

constra<strong>in</strong>t on the axial-vector component, one has<br />

A i ν(l; P) =<br />

6∑<br />

p i n(l; P) γ 5 A n ν(l; P) , i = +, 0, −, (6.16)<br />

n=1<br />

where (ˆl ⊥ ν = ˆl ν + ˆl · ˆP ˆP ν , γ ⊥ ν = γ ν + γ · ˆP ˆP ν )<br />

A 1 ν = γ · ˆl ⊥ ˆPν , A 2 ν = −i ˆP ν , A 3 ν = γ · ˆl ⊥ ˆl⊥ ,<br />

A 4 ν = iˆl ⊥ µ , A5 ν = γ⊥ ν − A3 ν , A6 ν = iγ⊥ ν γ · ˆl ⊥ − A 4 ν . (6.17)<br />

F<strong>in</strong>ally, requir<strong>in</strong>g also that D νρ (l; P) be an eigenfunction of Λ + (P), one obta<strong>in</strong>s<br />

D νρ (l; P) = S ∆ (l; P) δ νρ + γ 5 A ∆ ν (l; P) l⊥ ρ , (6.18)<br />

with S ∆ <strong>and</strong> A ∆ ν given by obvious analogues of equations(6.15) <strong>and</strong> (6.16), respectively.<br />

One can now write the Faddeev equation satisfied by Ψ 3 as<br />

[<br />

] ∫<br />

[<br />

]<br />

S(k; P) u(P) d 4 l<br />

A i µ (k; P) u(P) = −4<br />

(2π) M(k, l; P) S(l; P) u(P)<br />

4 A j ν (l; P) u(P) , (6.19)<br />

where one factor of “2” appears because Ψ 3 is coupled symmetrically to Ψ 1 <strong>and</strong> Ψ 2 , <strong>and</strong><br />

the necessary colour contraction has been evaluated: (H a ) bc (H a ) cb ′<br />

<strong>in</strong> equation (6.19) is<br />

with<br />

M(k, l; P) =<br />

[<br />

M00 (M 01 ) j ν<br />

(M 10 ) i µ (M 11 ) ij<br />

µν<br />

]<br />

= −2 δ bb ′. <strong>The</strong> kernel<br />

(6.20)<br />

M 00 = Γ 0+ (k q − l qq /2; l qq ) S T (l qq − k q ) ¯Γ 0+ (l q − k qq /2; −k qq ) S(l q ) ∆ 0+ (l qq ) , (6.21)<br />

where: 2 l q = l+P/3, k q = k+P/3, l qq = −l+2P/3, k qq = −k+2P/3 <strong>and</strong> the superscript<br />

“T” denotes matrix transpose; <strong>and</strong><br />

(M 01 ) j ν = tj Γ 1+<br />

µ (k q − l qq /2; l qq )<br />

×S T (l qq − k q ) ¯Γ 0+ (l q − k qq /2; −k qq ) S(l q ) ∆ 1+<br />

µν(l qq ) , (6.22)<br />

(M 10 ) i µ = Γ0+ (k q − l qq /2; l qq )<br />

×S T (l qq − k q )t i ¯Γ1 +<br />

µ (l q − k qq /2; −k qq ) S(l q ) ∆ 0+ (l qq ) , (6.23)<br />

(M 11 ) ij<br />

µν = t j Γ 1+<br />

ρ (k q − l qq /2; l qq )<br />

×S T (l qq − k q )t i ¯Γ1 +<br />

µ (l q − k qq /2; −k qq ) S(l q ) ∆ 1+<br />

ρν (l qq) . (6.24)<br />

2 This choice is expla<strong>in</strong>ed by equation(6.55) <strong>and</strong> the discussion thereabout.

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