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Tab Electronics Guide to Understanding Electricity ... - Sciences Club

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172 Chapter Six<br />

value of RE is known (1 Kohm) and the voltage across it is known (0.3<br />

volt), the current flow through RE can be easily calculated using<br />

Ohm’s law:<br />

E 0.3 volt<br />

I <br />

0.0003 amps or 300 microamps<br />

R 1000 ohms<br />

The current flow through RE is the same variable as the “emitter current<br />

flow” of Q1. Therefore, since the <strong>to</strong>tal current flow for both base<br />

and collec<strong>to</strong>r comes from the emitter, you know that the sum of the<br />

base current and collec<strong>to</strong>r current will equal 300 microamps. In addition,<br />

since the beta for Q1 is assumed <strong>to</strong> be 99, you know that the base<br />

current will be 99 times smaller than the collec<strong>to</strong>r current. Therefore,<br />

the base current will be approximately 3 microamps and the collec<strong>to</strong>r<br />

current will be approximately 297 microamps (297 microamps divided<br />

by 3 microamps 99), with both current flows adding up <strong>to</strong> the <strong>to</strong>tal<br />

emitter current flow of 300 microamps.<br />

Under the previous conditions, the emitter voltage of Q1 has already<br />

been determined <strong>to</strong> be 0.3 volt (i.e., the voltage across RE). The collec<strong>to</strong>r<br />

voltage of Q1 will be the V1 source voltage “minus” whatever voltage is<br />

dropped by the collec<strong>to</strong>r resis<strong>to</strong>r (RC). The voltage drop across RC can be<br />

calculated using Ohm’s law by multiplying the collec<strong>to</strong>r current<br />

(297 microamps) by the resistance value of RC (10,000 ohms):<br />

E IR (0.000297 amps)(10,000 ohms) 2.97 volts<br />

Therefore, the collec<strong>to</strong>r voltage will be<br />

30 volts 2.97 volts 27.03 volts<br />

Therefore, with V2 adjusted for 1 volt and an assumed beta of 99 for Q1,<br />

the collec<strong>to</strong>r voltage will be “about” 27 volts and the emitter voltage will<br />

be “about” 0.3 volt. Remember, all specified voltages in a typical schematic<br />

will be in reference <strong>to</strong> circuit common, or ground potential, unless the<br />

voltage is accompanied with a specific qualifying statement. Therefore,<br />

when measuring the collec<strong>to</strong>r voltage of Q1, you are actually measuring<br />

the voltage across RE as well as the voltage from emitter <strong>to</strong> collec<strong>to</strong>r<br />

of Q1.<br />

Now, assume that all other circuit conditions for Fig. 6-7c remain the<br />

same, with the exception that V2 is adjusted <strong>to</strong> 2 volts. Subtracting<br />

the typical 0.7-volt base-emitter junction drop, the voltage across RE

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