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Tab Electronics Guide to Understanding Electricity ... - Sciences Club

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Basic Electrical Concepts<br />

55<br />

present equal resistances. To calculate the voltage drops across the individual<br />

resis<strong>to</strong>rs, you might use Ohm’s law as in the previous example. Another<br />

way of calculating the same drops is by using the ratio method. To use the<br />

ratio method, calculate R <strong>to</strong>tal<br />

by adding all of the individual resistive values.<br />

Make a division problem with R <strong>to</strong>tal<br />

the divisor, and the dividend the resistive<br />

value of the resis<strong>to</strong>r for which the voltage drop is being calculated. Perform<br />

this division, and then multiply the quotient by the value of the<br />

source voltage. The answer is the value of the unknown voltage drop.<br />

Referring <strong>to</strong> Fig. 2-19, assume you desire <strong>to</strong> calculate the voltage drop<br />

across R1 using the ratio method. Start by finding R <strong>to</strong>tal<br />

:<br />

R <strong>to</strong>tal<br />

R 1<br />

R 2<br />

R 3<br />

2 ohms 3 ohms 5 ohms 10 ohms<br />

Next, make a division problem with R <strong>to</strong>tal<br />

as the divisor and R 1<br />

as the<br />

dividend and perform the division:<br />

2 ohms<br />

0.2<br />

10 ohms<br />

Finally, multiply this quotient by the value of the source voltage:<br />

(10 volts)(0.2) 2 volts<br />

The voltage dropped across R1 in Fig. 2-19 will be 2 volts. As an exercise,<br />

calculate the voltage drop across R1 using Ohm’s law. You should come<br />

up with the same answer.<br />

Series-Parallel Circuits<br />

In many situations, series and parallel circuits are combined <strong>to</strong> form<br />

series-parallel circuits (Fig. 2-20). In this circuit, R2 and R3 are in parallel,<br />

Figure 2-19<br />

Series circuit with<br />

unequal resistances.<br />

–<br />

+<br />

E 10 Vdc<br />

R 1 2<br />

R 2 3<br />

R 3 5

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