Electronic Circuit Analysis

174 Electronic Circuit Analysis
At f= 50 Hz,
R'=900Q
L
.. Transformer turns ratio
1
e = = - 53 ~f
E 21tfX E
2x3.14xSOx6-
n = =~ = t~O) = 15
It is Germanium transistor, V BE = 0.2SV
VB=VE+VBE
= I + 0.25 = 1.2SV
Assuming that the current through R1 is 10 I B ,
I R
= 250 ~ x 10
1 =2.5 rnA
Neglecting the loading effect due to base of the transistor and assuming that I B , flows
through RL also
R _ VB = 1.25
2 - IRI 2.SrnA
= 0.5 KQ
Vee - VB 16-1.25
R1 = = = 5.9 KQ
IRI 2.5 rnA
4.9 Class D: Operation
These are used in transmitters because their efficiency (11) is high::: 100%.
o
Fig. 4:30 Class D amplifier circuit
1+
VOp
Vo r ·A ,
J_ ~~--rot