25.07.2016 Views

Electronic Circuit Analysis

Create successful ePaper yourself

Turn your PDF publications into a flip-book with our unique Google optimized e-Paper software.

Multistage Amplifrers 39<br />

The equivalent circuit for the above transistor configuration is,<br />

hIe<br />

C<br />

Fig. 2.3 Equivalent circuit<br />

Suppose the value of C c is very large. Then at the low and medium frequencies, the impedance<br />

is negligible. So the equivalent circuit is as shown. We shall consider the effect of C E later.<br />

From the equivalent circuit,<br />

Vo = - h fe · i b· RL<br />

negative sign is used since it is NPN transistor. The collector current is flowing into the transistor.<br />

Input current, Ib = Vi Rs + R j<br />

For a transistor amplifier circuit in common emitter configuration,<br />

R j = hje + (1 + h fe ) ZE'<br />

Where ZE = RE in parallel with C E =<br />

Ay at low frequencies, (LF)<br />

1+ jroC E<br />

RE<br />

Vs<br />

Vo<br />

A=y<br />

~<br />

S<br />

Vo<br />

Ay(LF) = V.<br />

S<br />

When ro is large,<br />

(l+hfe)RE<br />

1+ jro C E RE<br />

can be neglected. So in the Mid Frequency range, (M.F.),<br />

-hfeRL<br />

Av (M.F) = R h<br />

s + ie<br />

In this expression, there is no for ro term. Hence in the mid frequency range, Ay is independent<br />

off or the gain remains constant, irrespective of change in frequency.

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!