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Electronic Circuit Analysis

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Tuned Amplifiers - I<br />

197<br />

5.3.1 Equivalent <strong>Circuit</strong> on the Output Side of the I Stage<br />

RI is the input resistance of the II stage.<br />

Ro is the output resistance of the I stage amplifier.<br />

II<br />

Fig. 5.8 Equivalent circuit<br />

The input IZI of the common emitter amplifier circuits will be less. So the output impedance of<br />

the circuit being coupled to one common emitter amplifier, should also have low IZI for impedance<br />

matching and to get maximum power transfer. So in order to reduce the impedance of the LC<br />

resonant circuit, to match the low IZI of the common emitter circuit, tapping is made in the LC tuned<br />

circuit. Tapped single tuned circuits are us~d in such applications.<br />

5.3.2 Expression for 'Inductance' for Maximum Power Transfer<br />

Let the tapping point divide the impedance into two parts LI and L 2 .<br />

Let LI = nL so that L2 = (1 - n)<br />

Writing Kirchoff's Voltage Law (KVL)<br />

VI = jroL . II - jro (L2 + M) 12<br />

o = -jro (LI + M) II + (R j + jroL 2 ) 12<br />

Where M is the mutual inductance between LI and L 2 . Solving equations 1 and 2,<br />

..... (1)<br />

..... (2)<br />

VI {Ri + jroL 2 )<br />

I = ---:----"-"--:--..,...:::--~<br />

I<br />

jroL (Ri + jroL 2 )+00 2 (L2 + M f<br />

..... (3)<br />

Hence the IZI offered by the coil along with input resistance ~i of the next stage is<br />

..... (4)<br />

..... (5)<br />

But roL2 much less than R i .<br />

As R i<br />

, the input resistance of transistor circuit II stage is KQ and much greater than roL2<br />

..... (6)

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