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Electronic Circuit Analysis

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28 <strong>Electronic</strong> <strong>Circuit</strong> <strong>Analysis</strong><br />

Example : 1.7<br />

For the JFET amplifier circuit shown in Fig. 1.31, if gm = 2500 ~(j, and Vm = 5 m V, what is the value<br />

ofVo?<br />

1 MO<br />

r----,--- + 30 V<br />

V, 0---1 1---+--1-+1<br />

Ca<br />

1 MO<br />

""":""'.f---i r--,---O Vo<br />

3 KO<br />

Solution:<br />

Fig. 1.31 <strong>Circuit</strong> diagram of Ex : 1.7<br />

1<br />

--=4000<br />

gm 2500 fl<br />

Open circuit output voltage, that is without considering R L<br />

, = (0.949) (5mV) = 4.75 mY.<br />

Output impedance is, Zo = Rs II<br />

1<br />

ḡm<br />

= 7500 0 II 400 0<br />

=3800<br />

This is the AC equivalent circuit. An AC source of 4.75 m V is in series drawn circuit with an<br />

output impedance of 380 O.<br />

5mV::1<br />

500n I<br />

3800<br />

Fig. 1.32 AC Equivalent circuit<br />

Therefore, AC voltage across the load resistor is,<br />

3000<br />

Vo = 3380 x 4.75 mV<br />

= 4.22 mV

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