The Java Language Specification, Third Edition

EXPRESSIONS Accessing Superclass Members using super 15.11.2
}
int x = 3;
void test() {
System.out.println("x=\t\t"+x);
System.out.println("super.x=\t\t"+super.x);
System.out.println("((T2)this).x=\t"+((T2)this).x);
System.out.println("((T1)this).x=\t"+((T1)this).x);
System.out.println("((I)this).x=\t"+((I)this).x);
}
class Test {
public static void main(String[] args) {
new T3().test();
}
}
which produces the output:
x= 3
super.x= 2
((T2)this).x=2
((T1)this).x=1
((I)this).x= 0
Within class T3, the expression super.x is treated exactly as if it were:
((T2)this).x
Suppose that a field access expression T.super.name appears within class C,
and the immediate superclass of the class denoted by T is a class whose fully qualified
name is S. Then T.super.name is treated exactly as if it had been the
expression ((S)T.this).name.
Thus the expression T.super.name can access the field named name that is
visible in the class named by S , even if that field is hidden by a declaration of a
field named name in the class named by T.
It is a compile-time error if the current class is not an inner class of class T or
T itself.
DRAFT
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