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Calculus 2nd Edition Rogawski

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SECTION 12.4 Area and Arc Length in Polar Coordinates 645<br />

y<br />

y<br />

r = sin 2 θ<br />

P<br />

π<br />

r = 4 sec( θ − 4<br />

)<br />

x<br />

FIGURE 13<br />

Q<br />

x<br />

FIGURE 17 Four-petaled rose r = sin 2θ.<br />

10. Find the area enclosed by one loop of the lemniscate with equation<br />

r 2 = cos 2θ (Figure 18). Choose your limits of integration carefully.<br />

5. Find the area of the shaded region in Figure 14. Note that θ varies<br />

from 0 to π 2 .<br />

6. Which interval of θ-values corresponds to the the shaded region in<br />

Figure 15? Find the area of the region.<br />

y<br />

−1 1<br />

y<br />

FIGURE 18 The lemniscate r 2 = cos 2θ.<br />

11. Sketch the spiral r = θ for 0 ≤ θ ≤ 2π and find the area bounded<br />

by the curve and the first quadrant.<br />

x<br />

8<br />

r = θ<br />

2 + 4θ<br />

2<br />

y<br />

r = 3 − θ<br />

12. Find the area of the intersection of the circles r = sin θ and<br />

r = cos θ.<br />

13. Find the area of region A in Figure 19.<br />

y<br />

r = 4 cos θ<br />

1 2<br />

FIGURE 14<br />

x<br />

FIGURE 15<br />

3<br />

x<br />

r = 1<br />

−1 1 2 4<br />

A<br />

x<br />

7. Find the total area enclosed by the cardioid in Figure 16.<br />

y<br />

FIGURE 19<br />

14. Find the area of the shaded region in Figure 20, enclosed by the<br />

circle r = 1 2 and a petal of the curve r = cos 3θ. Hint: Compute the<br />

area of both the petal and the region inside the petal and outside the<br />

circle.<br />

−2<br />

−1<br />

x<br />

y<br />

FIGURE 16 The cardioid r = 1 − cos θ.<br />

r = cos 3θ<br />

x<br />

r = 1 2<br />

8. Find the area of the shaded region in Figure 16.<br />

9. Find the area of one leaf of the “four-petaled rose” r = sin 2θ (Figure<br />

17). Then prove that the total area of the rose is equal to one-half<br />

the area of the circumscribed circle.<br />

FIGURE 20<br />

15. Find the area of the inner loop of the limaçon with polar equation<br />

r = 2 cos θ − 1 (Figure 21).

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