Tuyển tập 25 đề thi học sinh giỏi Hóa học lớp 9 (kèm đáp án) (by Dameva)
LINK BOX: https://app.box.com/s/o99ni841akj1du7thudv791t7d6gl511 LINK DOCS.GOOGLE: https://drive.google.com/file/d/1rxndliuwuCanNdIDkn77cCAwIFOWMvJF/view?usp=sharing
LINK BOX:
https://app.box.com/s/o99ni841akj1du7thudv791t7d6gl511
LINK DOCS.GOOGLE:
https://drive.google.com/file/d/1rxndliuwuCanNdIDkn77cCAwIFOWMvJF/view?usp=sharing
Create successful ePaper yourself
Turn your PDF publications into a flip-book with our unique Google optimized e-Paper software.
TUYỂN TẬP 50 ĐỀ THI HỌC SINH GIỎI MÔN HÓA HỌC LỚP 9 (<strong>kèm</strong> <strong>đáp</strong> <strong>án</strong>)<br />
C©u 2: 5,5®<br />
1. C¸c ®ång ph©n 1,5<br />
+ C 2 H 4 O 2 : CH 3 COOH , HCOOCH 3 , CH 2 (OH) CHO. 0,5<br />
........................................................<br />
0,5<br />
+ C 3 H 8 O: CH 3 CH 2 CH 2 OH , CH 3 CH(OH) CH 3 , CH 3 -O-CH 2 CH 3<br />
......................................<br />
0,5<br />
+C 5 H 10 : CH 2 = CHCH 2 CH 2 CH 3 , CH 2 = CH-CH(CH 3 )CH 3 , CH 2 = C(CH 3 ) –<br />
CH 2 CH 3 ,<br />
CH 3 -CH=CH-CH 2 CH 3 , CH 3 CH=C(CH 3 ) 2 .<br />
.......................................................................<br />
2. 2,0<br />
Theo ®Ò ra c«ng thøc cÊu t¹o cña c¸c chÊt lµ :<br />
A: CH 2 =CH-CH=CH 2 , B: CH 2 Cl-CH=CH-CH 2 Cl<br />
C: CH 2 OH-CH=CH-CH 2 OH. D: CH 2 OH-CH 2 - CH 2 -CH 2 OH<br />
..............................<br />
Ph−¬ng tr×nh hãa häc:<br />
1,4<br />
CH 2 =CH-CH=CH 2 + Cl 2 ⎯⎯→ CH 2 Cl-CH=CH-CH 2 Cl<br />
o<br />
t c<br />
CH 2 Cl-CH=CH-CH 2 Cl + 2NaOH ⎯⎯→ CH 2 OH-CH=CH-CH 2 OH.+2NaCl<br />
Ni, t<br />
CH 2 OH-CH=CH-CH 2 OH. + H o c<br />
2 ⎯⎯⎯→ CH 2 OH-CH 2 - CH 2 -CH 2 OH<br />
0<br />
170 C,<br />
H2SO4dac<br />
CH 2 OH-CH 2 - CH 2 -CH 2 OH ⎯⎯⎯⎯⎯⎯→ CH 2 =CH-CH=CH 2<br />
1,0<br />
t<br />
nCH 2 =CH-CH=CH , xt,<br />
p<br />
2 ⎯⎯⎯→ (-CH 2 -CH=CH-CH 2 -) n<br />
3. 2,0<br />
- DÉn hçn hîp khÝ qua dung dÞch Ca(OH) 2 d− ; CO 2 ®−îc gi÷ l¹i:<br />
CO 2 + Ca(OH) 2 → CaCO 3 + H 2 O<br />
- NhiÖt ph©n CaCO 3 thu ®−îc CO 2 :<br />
0<br />
t<br />
CaCO 3<br />
⎯⎯→ CaO + CO 2<br />
0,5<br />
................................................................................<br />
- DÉn hçn hîp khÝ cßn l¹i qua dung dÞch Ag 2 O d− trong NH 3 ; läc t¸ch thu ®−îc<br />
kÕt tña vµ hçn hîp khÝ CO , C 2 H 4 vµ NH 3 :<br />
NH3<br />
C 2 H 2 + Ag 2 O ⎯⎯⎯→ C 2 Ag 2 + H 2 O<br />
- Cho kÕt tña t¸c dông víi dd H 2 SO 4 lo·ng d− thu ®−îc C 2 H 2 :<br />
0<br />
t<br />
C 2 Ag 2 + H 2 SO 4 ⎯⎯→ C 2 H 2 + Ag 2 SO 4<br />
..........................................................<br />
- DÉn hçn hîp CO, C 2 H 4 vµ NH 3 qua dd H 2 SO 4 lo·ng d−, ®un nãng; thu ®−îc<br />
CO:<br />
2NH 3 + H 2 SO 4 → (NH 4 ) 2 SO 4<br />
. 2 4<br />
C 2 H 4 + H 2 O ⎯⎯⎯⎯→ d dH SO<br />
CH 3 CH 2 OH<br />
- Ch−ng cÊt dung dÞch thu ®−îc C 2 H 5 OH. T¸ch n−íc tõ r−îu thu ®−îc C 2 H 4 .<br />
0<br />
170 C,<br />
H2SO4dac<br />
CH 3 CH 2 OH ⎯⎯⎯⎯⎯⎯→ C 2 H 4 + H 2 O<br />
...............................................................<br />
C©u 3 . 4,0<br />
a. 1,5<br />
PTHH:<br />
+ LÇn thÝ nghiÖm 1: 2NaOH + H 2 SO 4 → Na 2 SO 4 + 2H 2 O (1)<br />
V× qu× tÝm hãa xanh, chøng tá NaOH d−. Thªm HCl:<br />
HCl + NaOH → NaCl + H 2 O (2)<br />
1,0<br />
0,75<br />
0,75<br />
<strong>25</strong>
Change language