Reasonin Rakesh Yadav

a
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(b)
(c)
12 fnuksa es a = 12 7 = 5 ('ks"kiQy)
hence 5 is E.D (E,D – Extra
Days)
vr% 5 vfrfjDr fnu gSA
In 67 days = 67 7
67 fnu es a = 67 7
hence 4 is E.D
= 4 (Remainder)
= 4 ('ks"kiQy)
In 41 days = 41
7 = 6 (Remainder)
41 fnu es a = 41
7 = 6 ('ks"kiQy)
hence 6 is E.D
vr% 6 vfrfjDr fnu
Similarly,
blh izdkj&
In 39 days 4 E.D
39 fnuksa es a 4 vfrfjDr fnu
In 26 days 5 E.D
26 fnuksa esa 5 vfrfjDr fnu
Here we found that the Extra
days always comes 0 to 6.
;gk¡ ge ikrs gS fd vfrfjDr fnuksa dh
la[;k ges'kk O vkSj 6 ds chp vkrh gSA
Extra days in months
eghuksa esa vfrfjDr fnu
Months are of Four types
eghus pkj izdkj ds gksrs gSA
(i) 28 days = 0 E.D
28 fnu = 0 vfrfjDr fnu
(ii) 29 days = 1 E.D
29 fnu = 1 vfrfjDr fnu
(iii) 30 days = 2 E.D
30 fnu = 2 vfrfjDr fnu
(iv)31 days = 3 E.D
31 fnu = 3 vfrfjDr fnu
Extra days in Years
o"kks± esa vfrfjDr fnu
Odd days in a Ordinary Year
= 1
lk/kj.k o"kZ es a fo"ke fnu = 1
Odd days in a Leap Year = 2
yhi o"kZ es a fo"ke fnu = 2
Ex.
Formula =
year + no. of Leap Year in these Year
7
o"kZ $ bl o"kZ esa yhi o"kks± dh la[;k
lw=k =
7
=Remainder/'sk"kiQy
Where, Leap Year/tgk¡] yhi o"kZ
No. of year
= =(Quotient)
4
o"kks± dh la[;k
=
=(HkkxiQy)
4
Find Odd days in 10 years
10 o"kks± es a fo"ke fnuksa dh la[;k Kkr dj
Leap years = 10 4
= 2 (Remainder)
yhi o"kZ = 10 4
= 2 (HkkxiQy)
odd days = year + 2
7
o"kZ + 2
fo"ke fnu = = 'ks"kiQy
7
= 10 2 = 12 7 7
=Remainder
= 5 (Remainder)/('ks"kiQy)
E.x Find odd days in 46, 99, 53, 76,
83 years respectively?
mnk- Øe'k% 46, 99, 53, 76, 83 o"kks± es
fo"ke fnuksa dh la[;k Kkr djsa\
In 46 years/o"kZ
Rakesh Yadav Sir
No. of Leap Years = 46 4 = 11
(Quotient)
yhi o"kks ± dh la[;k = 46 4
46 11
odd days =
7
(Remainder)
fo"ke fnu =
In 99 years,
99 o"kks± es a
= 11 (HkkxiQy)
= 57
7 = 1
46 11
= 57
7 7 = 1 ('ks"kiQy)
No. of Leap Years = 99 4
yhi o"kks± dh la[;k = 99 4
= 24 (Quotient)/(HkkxiQy)
99 24
odd days = = 123
7 7
99 24
o"ke fnu = = 123
7 7
= 4 (Remainder)('ks"kiQy)
In 53 year,
53 o"kks± es a]
No. of Leap Years = 53 4 = 13
(Quotient)
yhi o"kks ± dh la[;k= 53 4
53 13
odd days =
7
(Remainder)
53 13
fo"ke fnu =
7
In 75 years,
75 o"kZ
= 13 (HkkxiQy)
= 66
7
= 66
7 = 3
No. of Leap Years = 76 4 = 19
(Quotient)
yhi o"kks ± dh la[;k = 76 4
odd days/fo"ke fnu =
= 19 (HkkxiQy)
76 19
7
= 95 7 =4(Remainder)/('ks"kiQy)
In 83 Years
83 o"kZ]
No. of Leap Years/yhi o"kks ± dh la[;k
= 83 4
= 20 (Quotient)/(HkkxiQy)
odd days/fo"ke fnu =
83 20
7
= 103
7 =5(Remainder)/('ks"kiQy)
Thus, in 46, 99, 53, 76, 83
Years 1, 4, 3, 4, 5 Extra days
Respectively
Rakesh Yadav Readers Publication Pvt. Ltd
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