Reasonin Rakesh Yadav

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17. (d)
Age of mother (ekrk dh vk;q) = 2x
years
2x – 20 = x + 5
2x – x = 5 + 20
x = 25 years
Age of mother (ekrk dh vk;q ) = 2x
= 2 × 25 = 50 years
Age of father (firk dh vk;q)= 50 +
10 = 60 years
2x
x 3x/2
I II III
Suppose the number of fruits
in the second basked= x (ekuk
nwljh Vksdjh es a iQyksa dh la[;k x gS
Number of fruits in the first
basket (igyh Vksdjh esa iQyksa dh la[;k)
= 2x
Number of fruits in the third
basket (rhljh Vksdjh es a iQyksa dh la[;k)
3 3x
= 2x
4 2
Now,
3x
2x
x
303
2
4x 2x 3x
30 3
2
= 9x = 30 × 3 × 2
x = 30 3 2 20
9
Number of fruits in the first
basket (igyh Vksdjh esa iQyksa dh la[;k)
= 2x = 2 × 20 = 40
18. (b) 19 total age of boys (19 yM+dks
dh dqy vk;q) = 19 × 21 = 399 years
Total age of 19 boys and
teacher (19 yM+dksa vkSj vè;kid dh
dqy vk;q ) 20 × 22 = 440 years
Teacher's age (vè;kid dh vk;q) =
440 – 399
= 41 years
19. (d) The age of person is 6
years his father's age (O;fDr dh
vk;q 6 o"kZ rks mlds firk dh vk;q)
= 6 × 6 = 36 years
Therefore, the age of his
mother (vr%] mldh ekrk dh vk;q)
= 36 – 4 = 32 year
20. (b) Present age of the son
(iq=k dh orZeku vk;q)= 12 years
The father was 36 years old
when the boy was born. (tc iq=k dk
tUe gqvk ml le; firk dh vk;q 36 o"kZ)
= 12 × 3 = 36 years
0 + 12 = 12 years
and 36 + 12 = 48 years
Therefore, 4 years ago the boy
was (vr%] 4 o"kZ igys yM+ds dh vk;q) =
12 – 4 = 8 years
21. (d) Total number of persons in
the family (ifjokj esa dqy lnL;ksa dh
la[;k) = 2 + 2 + 1 = 5
22. (b) Mr. Prakash and his wife
= 2 Prakash's two married
brothers (fe- izdk'k vkSj mudh iRuh =
izdk'k ds 2 'kknh'kqnk HkkbZ) = 4
Two children (nks cPps) = 2
Total members (dqy lnL;) = 8
23. (d) Total number of ways in
which the committee can be
formed (,d lfefr xfBr djus ds dqy
izdkj) = 5 × 3= 15
But Ms. A refuses to be a
member of the committee in
which Mr. B is taken as a
member.
ijarq] Jherh A us lfefr dh lnL;rk ls euk dj
fn;k tcfd fe- B us lnL;rk xzg.k dj yh
Therefore, the required
answer (vr% vHkh"V mÙkj )
= 15 – 1= 14
Rakesh Yadav Sir
24. (c) 324 18; 289 17
18 + 17 = 35
441 21; 484 22
21 + 22 = 43
625 25; 400 20
2520 45
256 16; 729 27
16 + 27 = 43
25. (c) 25 have VCRs and each
VCR owner also has a TV.
Therefore, the TV owners who
have not VCRs
= 75 – 25 = 50
25 ds ikl oh-lh-vkj vkSj izR;sd oh-lhvkj
/kjd ds ikl ,d Vh-oh- Hkh gSA
vr% og Vh-oh- /kjd ftlds ikl oh-lhvkj
ugha gS
= 75 – 25 = 50
Now, 10 have all the three.
Therefore, 50 – 10 = 40 have
only TV.
vc] 10 ds ikl lHkh rhsuks a gS
vr%] 50 – 10 = 40 ds ikl dsoy Vh-oh-
26. (c) 3.5 + 0.2 = 3.7
3.7 + 0.4 = 4.1
4.1 + 0.8 = 4.9
4.9 + 1.6 = 6.5
6.5 + 3.2 = 9.7
27. (d) Suppose the number of
cows (ekuk xk;ksa dh la[;k) = x
Therefore, the number of
herdsmen (vr%] pjokgksa dh la[;k)
= x
According to question,
iz'ukuqlkj]
4 × 2x – 28 = x × 2 + x × 4
8x – 28 = 2x + 4x
8x – 6x = 28
28
x 14
2
28. (d) 16 ÷ 4 74
16 7
16
4 4
4
21 ÷ 7 33
21 3
21
3 33
7
81 ÷ 9 99
8 1 9
81
9 99
9
55 ÷ 5
55 10
55
11 1011
5
29. (c) fodYiksa ds }kjk
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