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Reasonin Rakesh Yadav

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12. (a) Using the proper notations<br />

in (a), we get the statement<br />

as:<br />

(lehdj.k ea s mfpr fpUg dk iz;ksx djds]<br />

ge dFku izkIr djrs gSA tSls)<br />

4 + 5 × 9 ÷ 3 – 4 = 4 + 5 × 3 –<br />

4 = 4 + 15 – 4 = 15<br />

13. (d) Using the proper notations<br />

in (d), we get the statement<br />

as:<br />

(lehdj.k ea s mfpr fpUg dk iz;ksx djds]<br />

ge dFku izkIr djrs gSA tSls)<br />

18 ÷ 6 × 7 – 5 + 2 = 3 × 7 – 5<br />

+ 2 = 21 – 5 + 2 = 18<br />

14. (d) Using the proper notations<br />

in (d), we get the statement<br />

as:<br />

(lehdj.k ea s mfpr fpUg dk iz;ksx djds]<br />

ge dFku izkIr djrs gSA tSls)<br />

2 × 5 – 6 + 2 = 6 or 10 – 6 + 2<br />

= 6 or 6 = 6, which is true.<br />

15. (a) Using the proper notations<br />

in (a), we get the statement<br />

as:<br />

(lehdj.k ea s mfpr fpUg dk iz;ksx djds]<br />

ge dFku izkIr djrs gSA tSls)<br />

52 – 4 × 5 + 8 ÷ 2 = 52 – 4<br />

× 5 + 4 = 52 – 20 + 4<br />

= 56 – 20 = 36<br />

16. (d) Using the proper notations<br />

in (d), we get the statement<br />

as:<br />

(lehdj.k ea s mfpr fpUg dk iz;ksx djds]<br />

ge dFku izkIr djrs gSA tSls)<br />

8 × 8 + 8 ÷ 8 – 8 = 8 × 8 + 1 –<br />

8 = 64 + 1 – 8 = 65 – 8 = 57<br />

17. (d) Using the proper notations<br />

in (d), we get the statement<br />

as:<br />

(lehdj.k ea s mfpr fpUg dk iz;ksx djds]<br />

ge dFku izkIr djrs gSA tSls)<br />

9 + 9 ÷ 9 – 9 × 9 = 9 + 1 – 9 ×<br />

9 = 9 + 1 – 81 = 10 – 81 = –71<br />

18. (c) Using the proper notations<br />

in (c), we get the statement<br />

as:<br />

(lehdj.k ea s mfpr fpUg dk iz;ksx djds]<br />

ge dFku izkIr djrs gSA tSls)<br />

5 × 2 ÷ 2 < 10 – 4 + 8 or 5 × 1<br />

< 18 – 4 or 5 < 14, which is<br />

true<br />

19. (c) Using the proper notations<br />

in (c), we get the statement<br />

as:<br />

(lehdj.k ea s mfpr fpUg dk iz;ksx djds]<br />

ge dFku izkIr djrs gSA tSls)<br />

5 × 2 + 1 = 3 × 4 – 1 or 10 + 1<br />

= 12 – 1 or 11 = 11, which is<br />

true.<br />

20. (d) Using the proper notations<br />

in (d), we get the statement<br />

as:<br />

(lehdj.k ea s mfpr fpUg dk iz;ksx djds]<br />

ge dFku izkIr djrs gSA tSls)<br />

1 × 3 ÷ 2 > 1 < 5 > 3 × 1 ÷ 2 or<br />

3<br />

2 > 1 < 5 > 3 , which is true<br />

2<br />

21. (c) Using the proper notations<br />

in (c), we get the statement<br />

as:<br />

(lehdj.k ea s mfpr fpUg dk iz;ksx djds]<br />

ge dFku izkIr djrs gSA tSls)<br />

8 – 4 ÷ 2 < 6 + 3 or 6 < 9,<br />

which is true<br />

22. (b) Using the proper notations<br />

in (b), we get the statement<br />

as:<br />

(lehdj.k ea s mfpr fpUg dk iz;ksx djds]<br />

ge dFku izkIr djrs gSA tSls)<br />

4 + 3 × 8 – 1 = 6 ÷ 2 + 24 or<br />

27 = 27, which is true<br />

23. (b) Using the proper notations<br />

in (b), we get the statement<br />

as:<br />

(lehdj.k ea s mfpr fpUg dk iz;ksx djds]<br />

ge dFku izkIr djrs gSA tSls)<br />

9 + 5 + 4 = 18 ÷ 9 + 16 or 18<br />

= 18, which is true<br />

24. (d) Using the proper notations<br />

in (d), we get the statement<br />

as:<br />

(lehdj.k ea s mfpr fpUg dk iz;ksx djds]<br />

ge dFku izkIr djrs gSA tSls)<br />

<strong>Rakesh</strong> <strong>Yadav</strong> Sir<br />

31 + 1 – 2 < 4 + 6 × 7 or 30 <<br />

46, which is true<br />

25. (a) Using the proper notations<br />

in (a), we get the statement<br />

as:<br />

(lehdj.k ea s mfpr fpUg dk iz;ksx djds]<br />

ge dFku izkIr djrs gSA tSls)<br />

7 + 7 – 7 ÷ 7 < 14 or 13 < 14,<br />

which is true<br />

26. (a) Using the proper notations in<br />

(a), we get the statement as:<br />

(lehdj.k ea s mfpr fpUg dk iz;ksx djds]<br />

ge dFku izkIr djrs gSA tSls)<br />

www.yoursmahboob.wordpress.com<br />

2 < 2 × 4 + 1 × 4 – 8 or 2 < 4,<br />

which is true<br />

27. (b) Using the proper notations<br />

in (b), we get the statement<br />

as:(lehdj.k ea s mfpr fpUg dk iz;ksx<br />

djds] ge dFku izkIr djrs gSA tSls)<br />

2 ÷ 1 + 10 × 1 < 6 × 4 or 12 <<br />

24, which is true<br />

28. (d) Using the proper notations in<br />

(d), we get the statement as:<br />

(lehdj.k ea s mfpr fpUg dk iz;ksx djds]<br />

ge dFku izkIr djrs gSA tSls)<br />

10 × 2 > 2 ÷ 1 × 10 ÷ 2<br />

or 20 > 10, which is true<br />

29. (b) Using the proper notations in<br />

(b), we get the statement as:<br />

(lehdj.k ea s mfpr fpUg dk iz;ksx djds]<br />

ge dFku izkIr djrs gSA tSls)<br />

14 = 2 × 4 × 2 – 2 ÷ 1<br />

or 14 = 14, which is true<br />

30. (a) Using the proper notations<br />

in (a), we get the statement<br />

as:<br />

(lehdj.k ea s mfpr fpUg dk iz;ksx djds]<br />

ge dFku izkIr djrs gSA tSls)<br />

8 ÷ 4 × 1 – 2 = 16 – 16 or 0<br />

= 0, which is true<br />

31. (b) Using the proper notations<br />

in (b), we get the statement<br />

as:<br />

(lehdj.k ea s mfpr fpUg dk iz;ksx djds]<br />

ge dFku izkIr djrs gSA tSls)<br />

16 + 2 – 4 = 6 + 8 or 14 = 14,<br />

which is true<br />

32. (d) Using the proper notations<br />

in (d), we get the statement<br />

as:<br />

(lehdj.k ea s mfpr fpUg dk iz;ksx djds]<br />

ge dFku izkIr djrs gSA tSls)<br />

20 + 4 ÷ 4 – 2 > 3 or 19 > 3,<br />

which is true<br />

33. (a) Using the proper notations<br />

in (a), we get the statement<br />

as:<br />

(lehdj.k ea s mfpr fpUg dk iz;ksx djds]<br />

ge dFku izkIr djrs gSA tSls)<br />

15 ÷ 5 + 3 = 2 × 3 or 6 = 6,<br />

which is true<br />

34. (d) Using the proper notations<br />

in (d), we get the statement<br />

as:<br />

44 <strong>Rakesh</strong> <strong>Yadav</strong> Readers Publication Pvt. Ltd

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