Reasonin Rakesh Yadav

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ifj.kke Lo:i] 46, 99, 53, 76,
83 o"kks± es Øe'k vfrfjDr fnu
1, 4, 3, 4, 5 gSA
±
a
a
a
a
a 8
7 = 1 odd days/fo"ke fnu 1322 o"kks± es fo"ke fnu
Odd days in 400 years
400 o"kks± esa fo"ke fnuksa dh la[;k
Note: If result of odd days comes
th
300 Years + 99 Years + 400 year (Leap Year)
more than 7 then we will
1 + 4 + 2 = 7
again divide these days by 7
But 7 can not be odd days,
and Remainder would be ‘Odd
days’
uksV% ;fn fo"ke fnuksa dh la[;k 7 ls T;knk
vk jgh gSA rks ge bl fnu dks iqu% 7 ls
hence = 7 = 0 odd day
7
ijarq 7 fo"ke fnu ugha gks ldrk gSA vr%
foHkkftr djsaxs vkSj fiQj tks 'ks"k cpsxk
7
ogh gekjk fo"ke fnu gksxk\
= 0 fo"ke fnu
7
Odd days in 100 years
Initial 400 Years calender
100 o"kks± es fo"ke fnu
used in next 400 to 800 years
99 years + 100th year (Ordinary
Result)
in every 400 years
and repeated again and again
99 o"kZ + 100oka o"kZ (lk/kj.k o"kZ)
4 days + 1 day = 5 days Extra
4 fnu + 1 fnu = 5 fnu vfrfjDr
vkjafHkd 400 o"kks dk dSys.Mj nwljs 400–
800 o"kks± es iz;ksx gksxk vksj izR;sd 400
o"kks± es ckj&ckj iz;ksx gksxkA
Odd days in 200 years
As in 400 year E.D = 0
200 o"kks± esa fo"ke fnu
400 o"kks± es vfrfjDr fnu = 0
In 100 Years = 5 days
Note:- Every multiple of 400 have
odd days = 0
×2 ×2
uksV% izR;sd 400 ds fo"ke fnu = 0
In 200 Years = 10 days
Now we can find odd days in
100 o"kks± es = 5 fnu
any no. of years
×2 ×2
vc ge fdlh Hkh o"kZ es fo"ke fnuks dh
200 o"kks± es = 5 fnu
la[;k Kkr dj ldrs gS
Ex. Odd days in 1700 Years
But 10 days can never be odd
days, hence we will divide it 1700 o"kks± es fo"ke fnu
by 7 again and remainder
would be odd days
1600 + 100
ijarq 10 fnu dHkh fo"ke fnu ugha gksrsA
0 + 5 = 5 days
vr% bls iqu% 7 ls foHkkftr fd;k tk;sxk
Ex. Odd days in 2100 Years
vkSj tks 'ks"kiQy cpsxk oks fo"ke fnu gksaxsA
2100 o"kks± es fo"ke fnu
10
7 = 3 (Remainder)/('ks"kiQy) 2000 + 100
Odd days in 300 years
0 + 5 = 5 days
300 o"kks± esa fo"ke fnuksa dh la[;k
Ex. Odd days in 1900 years
th
200 Years + 99 Years + 300 year (Ordinary Year)
1900 o"kks± es fo"ke fnu
3 + 4 + 1 = 8
1600 + 300
But 8 can not be odd days,
hence
0 + 1 = 1days
ijarq 8 fo"ke fnu ugh gks ldrk Ex. Odd days in 1322 years
Rakesh Yadav Sir
Ex.
1200 + 100
+22
0 + 5 + 5 = 10 days
In 22 year, 22 o"kZ es a
Leap years 22
5 = 4 (Quatiet)
yhio"kZ
22
5 = 4 (HkkxiQy)
Odd day= 22 4
7
fo"ke fnu = 22 4
7
=5 (Remainder)
= 5 ('ks"kiQy)
10 can not be odd days = 10 7
10 fo"ke fnu ugha gks ldrk = 10 7
= 3 Remainder
= 3 ('ks"kiQy)
Odd days in 1745 years
1745 o"kks± es a fo"ke fnuksa dh la[;k
1600 + 100
+45
0 + 5 + 0 = 5
NOW TYPE-I
To find the day of the week on a particular
date when no preference day is
given:
,d fuf'pr rkjh[k ij] lIrkg ds fnuks a dks Kkr djuk tc
dksbZ ojh;rk okys fnu u fn;s x;s gks
When we count no. of odd days on
the given particular date. Then we
write
fn;s x;s ,d fuf'pr rkjh[k ij ge fo"ke fnuks a dh la[;k
irk djrs gSA fiQj ge fy[krs gSA
Sunday for 0 odd day
jfookj ds fy;s 0 fo"ke fnu
Monday for 1 odd day
lkseokj ds fy;s 1 fo"ke fnu
Tuesday for 2 odd days
eaxyokj ds fy;s 2 fo"ke fnu
Wednesday 3 odd days
cq/okj ds fy;s 3 fo"ke fnu
Thursday 4 odd days
c`gLifrokj ds fy;s 4 fo"ke fnu
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