Reasonin Rakesh Yadav

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Ex.17
– (7 × 11) = 19
In 4 th column (20 × 10)
– (20 × 8) = 40
Find missing term?
yqIr la[;k Kkr djsa\
0 –1 –2
1 0 –1
2 ? 0
(a) 0 (b) –2
(c) –1 (d) 1
Sol. (d) In first column 0 + 1 = 1
Ex.18
1 + 1 = 2
In 2 nd column – 1 + 1 = 0
0 + 1 = 1
In 3 rd column – 2 + 1 = – 1
Find missing term?
yqIr la[;k Kkr djsa\
23 529 1024
21 441 144
19 361 ?
(a) 1441 (b) 3529
(c) 9361 (d) 8281
Sol. (d) In 1st row
– 1 + 1 = 0
(23)² = 529 On changing
places of 23
((23)² = 529, 23 ds vadks dk LFkku
cnyus ij)
(32)² = 1024 It becomes 32,
Then,
(;g 32 gks tkrk gS, rks (32)² = 1024)
In 2 nd row
(21)² = 441 On Changing
places of 21
(12)² = 144 it becomes
12, Then
In 3 rd row
(19)² = 361 on Changing
places of 19
(91)² = 8281 it becomes
91, then
Ex.19
0 2 4
2 6 3
3 ? 5
35 225216
(a) 0 (b) 2
(c) 1 (d) 4
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Sol. (c) In 1 st column (0)³ + (2)³
+ (3)³ = 35
Ex.20
In 2 nd column (2)³ + (6)³
+ (1)³ = 225
In 3 rd column (4)³ + (3)³
+ (5)³ = 216
Ans = 1
Find the missing term.
yqIr la[;k Kkr djsa\
67 91 45
78 90 36
? 81 27
(a) 95 (b) 98
(c) 105 (d) 111
Sol. (c) In third column 4
+ 5
Ex.21
= 9 × 4 = 36
3
+
6 = 9 × 3 = 27
In 2 nd column 9
+ 1
= 10 × 9 = 90
9
+
0
= 9 × 9 = 81
In 1 st column 6
+ 7
= 13
× 6 = 78
7
+
8
= 15 × 7 = 105
Find missing term.
yqIr la[;k Kkr djsa\
4 5 6
2 3 7
1 8 3
21 98 ?
(a) 94 (b) 76
(c) 73 (d) 16
Sol. (a) In 1 st column 4² + 2² +
1² = 21
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Ex.22
In 2 nd column 5² + 3² +
8² = 98
In 3 rd column 6² + 7² +
3² = 94
Find missing term
yqIr la[;k Kkr djsa\
3 8 10
6 56 90
(a) 5 (b) 0
(c) 7 (d) 3
Sol. (a) In all columns
3² – 3 = 6
8² – 8 = 56
2 ? 1
2 20 0
10² – 10
= 90
2² – 2 = 2
5² – 5 = 20
1² – 1 = 0
In Circle In circle pattern can be
of "Number Series", "Logic in opposite
sector of circle"
o`Ùk esa o`Ùk iSVuZ es a foijhr [kaMksa dh la[;k Js.kh
es a gks ldrh gSA
Ex.23 Find missing term in circle?
o`Ùk es a yqIr in Kkr djsa\
? 8
216 64
(a) 1 (b) 512
(c) 9 (d) 8
Sol. (b) In this circle pattern is
made by Series of cube of
even numbers
;g o`Ùk iSVuZ le la[;kvksa ds ?ku ds
Js.kh }kjk fufeZr gSA
2³ = 8, 4³ = 64, 6³ = 216, (8)³
= 512
Ex.24 Find missing term.
yqIr la[;k Kkr djsa\
? 3
5
22
8
13
(a) 1 (b) 26
(c) 39 (d) 45
Sol. (c) In this circle the following
series is set
bl o`Ùk es a fuEufyf[kr Js.kh vuqlj.k djrh gSA
×2 –1
3 5
Ex.25
×2–2
8
×2 –3
13
Find missing term
yqIr la[;k Kkr djsa\
? 1
2
8
5 3
×2 –4 ×2 –5
22 39
(a) 10 (b) 15
(c) 13 (d) 12
Sol. (c) In this circle the series is
set clockwise from 1.
bl o`Ùk es a Js.kh ?kM+h dh okekorZ xfr dk
vuqlj.k djrh gSA
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