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Veto q&a 7 Month22 (1)

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Q & A<br />

@hangout<br />

WHen train beCOMes MatHs<br />

tOtal<br />

Plus<br />

iymw A¿-¼md<br />

Q<br />

Q<br />

Q<br />

A train 100m long is running at the speed of 30 km /hr.<br />

Find the time taken by it to pass a man standing near<br />

the railway time.<br />

⎛ 5 ⎞ 25<br />

Speed of the train = ⎜30 × ⎟m/s<br />

= m/s<br />

⎝ 18 ⎠ 3<br />

Distance moved in passing the standing man = 100 m<br />

100 3<br />

Required time taken = = 100 × = 12Sec<br />

⎛25 ⎞ 25<br />

⎜ ⎟<br />

⎝ 3 ⎠<br />

speed changing in m/s or km/hr<br />

‘x’ km/hr = x × 5 m/s<br />

18<br />

x m/s =<br />

⎛ 18 ⎞<br />

⎜x<br />

× ⎟ km/hr<br />

⎝ 5 ⎠<br />

A Speed of 14 meters per second is the same as<br />

⎛ 18 ⎞<br />

14 m/s = ⎜14<br />

× ⎟km/hr = 50.4 km/hr<br />

⎝ 5 ⎠<br />

In what time will a train 100m long cross an electric<br />

pole, if its speed be 180 km/hr<br />

Length of the train = 100 m<br />

Speed = 180 × 5 = 50 m/s<br />

18 100<br />

Time taken to cross the electric pole = = 2 sec<br />

50<br />

Length of a train ‘L’ meters is passing a pole or<br />

a standing man or a signal light is equal to the<br />

time taken by the train to cover ‘L’ meter.<br />

time taken =<br />

Q A man is standing on a railway bridge which is 180<br />

m long. He finds that a train crosses the bridge in<br />

20 sec by himself in 10 sec. Find the length of the<br />

train and its speed.<br />

Let the length of the train be ‘a’ meter.<br />

Q&A Bonus<br />

length of the train<br />

speed<br />

Then the train cover ‘a’ meter in ‘10sec’ and at<br />

‘180m’ in ‘20 sec’<br />

a a+<br />

180<br />

∴ =<br />

10 20<br />

∴ 20 a = 10(a+180)<br />

10a = 1800<br />

a = 180 m<br />

Length of the train = 180 m<br />

Speed of the train = 180 m/s = 18 m/s<br />

10<br />

18<br />

∴ 18× = 64.8km/hr<br />

time taken by a train of length ‘l’ meters and a<br />

stationary object of length ‘b’ meters is the time<br />

taken by the train cover ‘(l+b)’ meters<br />

Q How long does a train 110 m long running at the<br />

speed of 72 km/hr taken to cross a bridge 132<br />

meters in length<br />

Speed = 72 km/hr = 72× 5 = 20 m/sec<br />

18<br />

Total distance covered = 110+132 = 242 m<br />

⎛242<br />

⎞<br />

∴Required time = ⎜ ⎟ Sec = 12.1 sec<br />

⎝ 20 ⎠<br />

Q The length of the bridge, which a train ‘130 m’<br />

long and travelling at ‘45 km/hr’ can cross in ‘30<br />

seconds’ is<br />

⎛ 5 ⎞ 25<br />

Speed = ⎜45× ⎟=<br />

m/s<br />

⎝ 18 ⎠ 3<br />

time = 30 sec<br />

bridge length be take ‘a’ meter<br />

Then ; a + 130 25<br />

= m/s<br />

30 2<br />

∴2(a+130) = 25 x 30<br />

2a + 260 = 750<br />

a = 245 m<br />

Length of the bridge = 245 m<br />

The headquarters of Kerala Bhasha Institute - nalanda (thiruvananthapuram) 37

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