09.02.2019 Views

Veto q&a 7 Month22 (1)

Create successful ePaper yourself

Turn your PDF publications into a flip-book with our unique Google optimized e-Paper software.

Q A train 800 meters long is running at a speed of 78<br />

km/hr. If it crosses a tunnel in one minute. What is<br />

the length of the tunnel (in meters)<br />

Speed<br />

Time = 1 minute = 60 sec<br />

Let the length of the tunnel be ‘a’ meter<br />

800 + a 65<br />

Then, =<br />

60 3<br />

3 (a+800) = 3900<br />

3a = 3900 - 2400<br />

a = 500<br />

Q A train 150 m long is running with a speed of 68<br />

km/h. In what time will it pass a man who is running<br />

at 8 km/h in the same direction in which the train<br />

is going?<br />

38<br />

⎛ 5 ⎞ 65<br />

= ⎜78 × ⎟ m/sec = m/s<br />

⎝ 18 ⎠ 3<br />

Speed of the train relative to the man = (68-8) km/hr<br />

⎛ 5 ⎞ 50<br />

= ⎜60 × ⎟=<br />

m/s<br />

⎝ 18 ⎠ 3<br />

Time taken by the train to cross the man<br />

50<br />

= Time taken by it to cover 150 m at m/sec<br />

3<br />

3<br />

= 150 × = 9 sec<br />

50<br />

Q A train 220 m long is running with a speed of 59<br />

km/h. In what time will it pass a man who is running<br />

at 7 km/h in the direction opposite to that in which<br />

the train is going?<br />

Speed of the train related to man<br />

= (59+7) km/h = 66 km/h<br />

5 55<br />

= 66 × = m/sec<br />

18 3<br />

Time taken by the train to cross the man<br />

55<br />

= Time taken by it to cover 220 m at m/sec<br />

3<br />

3<br />

= 220 × = 12sec 55<br />

• suppose two trains or two bodies are moving in<br />

the same direction at ‘a m/s’ and ‘b m/s’, where<br />

u>v, then their relative speed = (u-v) m/s<br />

• suppose two trains or two bodies are moving in<br />

the opposite direction at ‘a m/s’ and ‘b m/s’ then<br />

their relative speed = (u+v) m/s<br />

Q&AUbdn current affairs & gk<br />

www.vetopsc.org<br />

follow us: facebook.com/vetotrivandrum<br />

@hang out<br />

Q A train passes a station platform in 36 seconds and<br />

a man standing on the platforms in 20 seconds. If<br />

the speed of the train is 54 km/hr, what is the length<br />

of the platform<br />

Speed = 54 km/h<br />

5<br />

= 54 × = 15m/sec<br />

18<br />

Length of the train = (15 x 20) m = 300 m<br />

Let the length of the platform be ‘x’ meter<br />

x + 300<br />

Then, = 15<br />

36<br />

⇒ x+300 = 540<br />

∴ x = 240 m<br />

Q A man running at ‘9 km/h’ along side a railway track<br />

is 240 meters ahead of the engine of a 120 meter<br />

long train running at 45 km/h in the same direction.<br />

In how much time will the train pass the man<br />

Speed of train relative to man = 45 - 9 = 36 km/h<br />

5<br />

⇒ 36 × = 10m/sec<br />

18<br />

Distance to be covered = (240 + 120) = 360 m<br />

360<br />

∴Time taken = = 36 sec<br />

10<br />

Q A train 110 meters long is running with a speed of<br />

60 km/h. In what time will it pass a man who is<br />

running at 6 km p/h in the direction opposite to that<br />

in which the train is going<br />

Speed of train relative to man = 60 + 6 = 66 km/h<br />

5 55<br />

66 x = m / s<br />

18 3<br />

∴Time taken to pass the man<br />

⎛ 3 ⎞<br />

= ⎜110 × ⎟sec<br />

= 6sec<br />

⎝ 55 ⎠<br />

Q Two train are moving in opposite direction at 60 km/h<br />

and 90 km/hr. Their length are 1.10 km and 0.9 km<br />

respectively. The time taken by the slower train to<br />

cross the faster train in seconds<br />

Relative speed = 60 + 90<br />

= 150 km/h<br />

5 125<br />

= 150 × = m/sec<br />

18 3<br />

Distance covered = (1.10 + 0.9) km<br />

= 2 km = 2000 m<br />

Required time = Distance<br />

Speed<br />

March 2018

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!