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Veto q&a 7 Month22 (1)

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Q<br />

@hang out<br />

2000 3<br />

= = 2000 × = 48sec<br />

125 125<br />

3<br />

Two trains, one from Howrah to Patna and other<br />

from Patna to Howrah, starts simultaneously.<br />

After they meet, the trains reach their destinations<br />

after 9 hours and 16 hours respectively. The ratio<br />

of their speed is?<br />

Let the name of the trains be A and B<br />

Then, (A’s speed) : (B’s speed) = b : a<br />

= 16 : 9<br />

= 4 : 3<br />

If two trains (or bodies) start at same time from<br />

points A and B towards each other and after<br />

crossing they take a and b see in reaching B<br />

and A respectively, then<br />

A’s speed : B’s speed = b : a<br />

Q Two goods train each 500 m long, are running in<br />

opposite direction on parallel tracks. Their speed<br />

are 45 km/h and 30 km/hr respectively. Find the<br />

time taken by the slower tarin to pass the driver of<br />

the fasterone<br />

Relative speed = 45 + 30 = 75 km/h<br />

5 125<br />

= 75× = m/sec<br />

18 6<br />

Distance covered = 500 + 500 = 1000 m<br />

Required time = Distance<br />

Speed<br />

1000 6<br />

= = 1000 × = 48 sec<br />

125 125<br />

6<br />

Q Two trains of equal length are running on parallel<br />

lines in the same direction at 46 km/hr and 36 km/<br />

hr. The faster train passes the slower train in 36<br />

seconds. The length of the each train is<br />

Let the length of the each train be ‘a’ meters<br />

Then, distsance covered = 2a meters<br />

Relative speed = 46 - 36<br />

5 25<br />

= 10 × = m/sec<br />

18 9<br />

2a<br />

25<br />

=<br />

36 9<br />

Q<br />

Q<br />

Q<br />

25×<br />

36<br />

2a = = 100<br />

9<br />

a = 50 m<br />

A train 108 m long moving at the speed of 50 km/hr<br />

crosses a train 112 m long coming from opposite<br />

direction in 6 seconds. What is the speed of the<br />

second train is?<br />

Let the speed of second train be ‘a’ meter<br />

Relative Speed = (50 + a) km/hr<br />

5<br />

= (50 + a) x m/s<br />

18<br />

+<br />

= 250 5 a m / s<br />

18<br />

Distance covered = 108 + 112 = 220 m<br />

∴ Distance = Time<br />

Speed<br />

220<br />

= 6<br />

250 + 5a<br />

⇒ 250 + 5a = 660<br />

⇒ a = 82 km/hr<br />

A man setting in a train which is travelling at 50 km/h<br />

observes that a goods train, travelling in opposite<br />

direction, takes 9 seconds to pass him. If the goods<br />

train is 280 m long, find its speed<br />

Relative speed =<br />

= 62 km/h<br />

280<br />

9<br />

m/sec<br />

280 18<br />

= × = 112 km/h<br />

9 5<br />

Speed of the goods train = 112 - 50<br />

A train X speeding with 120 km/h crosses another<br />

train Y, running in the same direction, in 2 minutes.<br />

If the lengths of the trains X and Y be 100 m and<br />

200 m respectively, what is the speed of train Y?<br />

Let the speed of train Y be ‘a’ km/hr<br />

Speed of ‘X’ relative to ‘Y’ = (120 - a) km/hr<br />

5<br />

= (120 − a) m / sec<br />

18<br />

600 − 5a = m / sec<br />

18<br />

Distance covered = 100 + 200 = 300 m<br />

Distance =Time<br />

Speed<br />

Q&A Bonus<br />

Kerala Bhasha Institute comes under - Department of Cultural affairs<br />

39

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