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Veto q&a 7 Month22 (1)

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2018<br />

April<br />

@hang out<br />

Q<br />

t1 7<br />

=<br />

4 4<br />

1<br />

4 7<br />

4<br />

Remainder = 3<br />

3<br />

t<br />

2<br />

15<br />

=<br />

3<br />

4 4<br />

4 15<br />

Remainder = 3 12<br />

Answer = 3<br />

3<br />

Sum of the 25 terms of an AP is 400. Find the<br />

13 th term<br />

n<br />

Sum of n terms = ( 2 a+ ( n− 1) d)<br />

= 400<br />

2<br />

25<br />

( 2 a+ (25 − 1) d)<br />

= 400<br />

2<br />

25 ( 2 a+ 24 d)<br />

= 400<br />

2<br />

400×<br />

2<br />

2a+24d =<br />

25<br />

2a+24d = 32<br />

32<br />

a+12d = = 16<br />

2<br />

a+12d = 16<br />

th<br />

13 term = a+12d =16<br />

Q<br />

Q<br />

What is the sum of the 20 consecutive terms of<br />

the AP 10, 15, 20....<br />

Sum of ‘n’ terms<br />

20<br />

= ( 2 × 10 + (20 − 1)5 )<br />

2<br />

n<br />

= ( 2 a+ ( n−1)<br />

d)<br />

2<br />

20<br />

= ( 20 + 19 × 5 )<br />

2<br />

20<br />

= × 95 + 20<br />

2<br />

= 10x115<br />

= 1150<br />

The sum of 10 th term and 20 th term of an AP is<br />

60. What is the sum of 14 th and 16 th term<br />

10 th term = a + 9d<br />

20 th term = a + 19d<br />

Sum = (a + 9d) + (a + 19d) = 60<br />

2a+ 28d = 60 ------ (1)<br />

14 th term = a + 13d<br />

16 th term = a + 15d<br />

Sum = (a + 13d) + (a + 15d)<br />

2a+ 28d - Equation--- (1)<br />

∴2a+ 28d = 60<br />

Selected Previous Year Questions<br />

Q<br />

Q<br />

Find the 15 th term of an arithmatic progression whose<br />

first term is 2 and the common difference is 3<br />

a) 45 b) 38 c) 44 d) 40<br />

ans: c) 44<br />

n th term of AP = a + (n-1)d<br />

= 2 + (15 -1) 3<br />

= 2 + 42 = 44<br />

What is the sum of the first 15 terms of an<br />

AP whose 11 th and 7 th terms are 5.25 and 3.5<br />

respectively<br />

a) 56.25 b) 60 c) 52.5 d) none of these<br />

ans: a) 56.25<br />

a + 10d = 5.25 ------- (1)<br />

a + 6d = 3.25 ------- (2)<br />

(1) - (2) = 4d = 2, d =1/2<br />

a + 5 = 5.25, a = 0.25 = 1/4<br />

15 ⎛ 1 1⎞<br />

S15<br />

= ⎜2× + 14 × ⎟<br />

2 ⎝ 4 2⎠<br />

15 ⎛1 14 ⎞<br />

= ⎜ + ⎟<br />

2 ⎝2 2 ⎠<br />

15 15 225<br />

= × = = 56.25<br />

2 2 4<br />

Q The sum of the first 100 numbers 1 to 100 is<br />

divisible by<br />

a) 1, 2, 4, 8 b) 2 & 4<br />

c) 2 d) none<br />

ans: c) 2<br />

The sum of the first 100 natural numbers is<br />

40 Q&AUbdn current affairs & gk<br />

www.vetopsc.org<br />

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