Veto q&a 7 Month22 (1)

2018
June
Q
4000 × 450
∴Share of Profit of A = = Rs. 300
6000
By selling 15 horses a man gains profit equal to selling
price of 6 horses. Find his gain percent.
a) 66% b) 66 %
3
c) 67% d) 67 %
2
2
ans: b) 66 % 3
Let selling price of 1 horse be Rs. 1
∴Selling Price of 15 horses = 15 x 1 = Rs. 15
and Profit = 6 x 1 = Rs. 6
C.P = 15 - 6 = Rs. 9
6 2
∴Profit % = x 100 = 66 %
9 3
1
Q The value of 7 is
1−
12
2 5
a) 0 b) 2 c) 2 d) 5
1 1 12 2
= = = 2
7 5
1−
5 5
12 12
5
ans: c) 2 2
2 2
Q What should come in the place of the question mark (?)
(125) 2.4 x (25) 3.2 ÷(5) 4.8 = (5) ?
a) 2.4 b) 8.8 c) 4.8 d) 3.2
ans: b) 8.8
x 3
2.4
2
3.2 4.8
( 5) = ( 5 ) × ( 5 ) ÷ ( 5)
6.4
x 7.2 5
( 5) = ( 5)
×
4.8
5
x 7.2 1.6
( 5) = ( 5)
× 5
8.8
= 5 x = 8.8
Q A is twice as fast as B and B is twice as fast as C.
The distance covered by C in 54 min will be covered
by A in --------
a) 216 min b) 27 min
c) 108 min d) 13.5 min
ans: d) 13.5 min
A = 2B
Q
Q
Q
@hang out
B = 2C
∴
C takes 54 min
So B would cover the same distance in help of the
time = 54/2 = 27
So, Time taken by A 27/2 = 13.5 min
If the length and breadth of a rectangle are 20 cm and
15 cm respectively. Find its diagonal
a) 24 cm, b) 30 cm
c) 32 cm d) 25 cm
ans: d) 25 cm
Diagonal =
2 2
L + B
= (20) + (15)
= 400 + 225
= 625
= 25
2 women and 10 children together take 8 days to
complete a piece of work. How many days will 10
children alone take to complete the piece of work if 8
women can complete the piece of work in 6 days?
a) 15 b) 12 c) 10 d) 24
ans: b) 12
Work of 8 women for 6 days = 1
1 1
Work of 1 women for 1 days = =
8x6 48
1
Work of 2 women for 8 days = x 2 x 8 = 1/3
Work of 10 children for 8 days = 1 - = 2/3
1 2 1
Work of 10 children for 1 day = × =
8 3 12
∴10 Children along will complete the work
8x3
2
= = 12 days
2 2
48 1
3
A man riding a bicycle, complete one lap of a circular
field along its circumference at the speed of 79.2 km/
hr in 2 minutes 40 seconds. What is the area of the
field?
a) 985600 sq. m b) 848500 sq. m
c) 795600 sq. m d) cannot determined
ans: a) 985600 sq. m
Perimeter of the field = Speed x Time
5
= 79.2× × 160
18
54
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