Veto q&a 7 Month22 (1)

@hang out
2018
April
Q Find the sum of 26 terms of the progression 50,
55, 60, ...
n
= ⎣⎡ 2a+ ( n−1)
d⎦⎤
2
26
= ( 2 × 50 + ( 26 − 1 ) 5 )
2
26
= ( 100 + 125 )
2
26
= × 225 = 13 x 225 = 2925
2
Q
Choose the number which is not suitable for the
given progression 7, 15, 23, ...
a) 103 b) 71 c) 87 d) 64
t 1
= 7
d = 8
For option (a) 103 - t1 = x
d x
ie, 103 - 7 = 96
12
8 96
8
16
16
0
Remainder is 0. Thererfore, this number is a part
of this progression
For option (b) 71 - 7 = 64
Remainder is 0.
8
8 64
64
0
For option (c) 87 - 7 = 80
Remainder is 0.
10
8 80
80
0
For option (d) 64 - 7 = 57
Q
7
8 57
56
1
Remainder is#0. Therefore this number is not a
part of this progression.∴Ans option (d)
Q Find the common multiple of the progression 36,
108, 324, ...
second term
Common Ratio (r) =
first term
Q Find x for the geometric progression 900, x, 100
Q Find the 7 th term of the geometric progression 10,
30, 90 ...
Q
Find the number which is a term in the progression
12, 21, 30, ......
1121
a) 10000 b) 1001 9 10089
9
c) 10101 d) 10100
10
a = 12, d = 9
9
18
(Take option (c) 10101 - 12 = 18
10089
9
Remainder is 0. ∴This is a term of 9
this progression
0
t2
108
r = = = 3
t 36
1
x= t1×
t3
= 900 × 100 = 90000 = 300
n th term = ar n-1
= 10 x 3 7-1
= 10 x 3 6 = 10x729 = 7290
The algebraic equation of an AP is 8n-1. What
will we get as remainder when we divide the
terms of this AP by 4
First term of AP is (t 1
) = 8 x 1 - 1 = 7
t 2
= 8 x 2 - 1 = 15
t 3
= 8 x 3 - 1 = 23
AP = 7, 15, 23, ......
Q&A Bonus
the aligarh movement was founded by - Sir Syed ahmed Khan
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