Precise Orbit Determination of Global Navigation Satellite System of ...
Precise Orbit Determination of Global Navigation Satellite System of ...
Precise Orbit Determination of Global Navigation Satellite System of ...
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Chapter 6 Algorithms <strong>of</strong> <strong>Orbit</strong> <strong>Determination</strong> <strong>of</strong> IGSO, GEO and MEO <strong>Satellite</strong>s<br />
If assuming<br />
T<br />
k<br />
−1 −1<br />
k k xk A = H R H + P′<br />
A<br />
A<br />
A<br />
11<br />
12<br />
21<br />
22<br />
T −1<br />
k Rk<br />
Gk<br />
T −1<br />
k Rk<br />
H k<br />
T −1<br />
k Rk<br />
Gk<br />
T −1<br />
ϖ −1<br />
ϖ<br />
k Rk<br />
yk<br />
+ Px′<br />
xk′<br />
= H<br />
= G<br />
= G<br />
b1<br />
= H<br />
b = G R<br />
ϖ<br />
y ,<br />
2<br />
T<br />
k<br />
−1<br />
k<br />
we can get<br />
~ ϖ −1<br />
xk = A11<br />
b1<br />
− A<br />
~ ϖ −1<br />
= −A<br />
A A<br />
z k<br />
where<br />
−1<br />
11<br />
22<br />
k<br />
k<br />
−1<br />
−1<br />
11 A12<br />
A22<br />
b2<br />
−1<br />
−1<br />
21 11 b1<br />
+ ( A22<br />
−1<br />
22<br />
−1<br />
21)<br />
+ A<br />
−1<br />
22<br />
A<br />
−1<br />
21 A11<br />
A12<br />
A<br />
−1<br />
22<br />
) b<br />
2<br />
70<br />
(6-20)<br />
(6-21)<br />
A = ( A11<br />
− A12<br />
A A<br />
(6-22)<br />
If matrices D and C are positive definite and others are arbitrary matrices, following relation holds<br />
−1<br />
−1<br />
−1<br />
−1<br />
−1<br />
−1<br />
( ACB + D)<br />
= D − D A(<br />
BD A + C ) BD<br />
(6-23)<br />
− 1<br />
From Eq.(6-23), A11 becomes<br />
A<br />
−1<br />
T −1<br />
−1<br />
T −1<br />
T −1<br />
−1<br />
T −1<br />
−1<br />
11 = [ H k Rk<br />
H k + Px′<br />
− H k Rk<br />
Gk<br />
( Gk<br />
Rk<br />
Gk<br />
) Gk<br />
Rk<br />
H k ]<br />
k<br />
{ } 1<br />
−1<br />
T −1<br />
−1<br />
T −1<br />
−1<br />
T −1<br />
−<br />
Px′ + H k [ Rk<br />
− Rk<br />
Gk<br />
( Gk<br />
Rk<br />
Gk<br />
) Gk<br />
Rk<br />
] H<br />
k<br />
T −1<br />
−1<br />
T −1<br />
−1<br />
T −1<br />
−1<br />
T −1<br />
P x′<br />
− P { } k x′<br />
H<br />
k k [ Rk<br />
− Rk<br />
Gk<br />
( Gk<br />
Rk<br />
Gk<br />
) Gk<br />
Rk<br />
] + H k Px′<br />
H<br />
k k H k Px′<br />
k<br />
T<br />
T<br />
T −1<br />
−1<br />
T −1<br />
−1<br />
−1<br />
P x′<br />
− P { } k x′<br />
H<br />
k k H k Px′<br />
H<br />
k k + Rk<br />
I k − Gk<br />
( Gk<br />
Rk<br />
Gk<br />
) Gk<br />
Rk<br />
] H k Px′<br />
k<br />
= k<br />
=<br />
=<br />
The gain matrix is defined as<br />
K<br />
[ (6-24)<br />
{ } 1<br />
T<br />
T −1<br />
−1<br />
T −1<br />
−1<br />
−<br />
H P′<br />
H + R [ I − G ( G R G ) G R ]<br />
T<br />
k = Px′<br />
H<br />
k k k xk<br />
k k k k k k k k k<br />
(6-25)<br />
Substituting Eq.(6-22) into Eq.(6-20), taking into account Eq.(6-27) yields<br />
~ ϖ ϖ ϖ<br />
T −1<br />
T −1<br />
−1<br />
T −1<br />
ϖ<br />
x = x′<br />
− K H x′<br />
+ ( I − K H ) P′<br />
H R [ I − G ( G R G ) G R ] y<br />
(6-26)<br />
k<br />
k<br />
k<br />
k<br />
k<br />
k<br />
k<br />
xk<br />
Assuming<br />
−1<br />
[ I − G<br />
T −1<br />
( G R G<br />
−1<br />
T −1<br />
−1<br />
−1<br />
) G R ] = [ R − R G<br />
T −1<br />
( G R G<br />
−1<br />
T −1<br />
) G R ] = W<br />
Rk k k k k k k k k k k k k k k<br />
then<br />
( I − K H<br />
T −1<br />
) P′<br />
H R [ I − G<br />
T −1<br />
( G R G<br />
−1<br />
T −<br />
) G Rk<br />
k<br />
k<br />
xk<br />
= ( I − K H ) P′<br />
H W<br />
k k xk<br />
k<br />
T<br />
k<br />
k<br />
−1<br />
' ' T ' T −1<br />
'<br />
x − Px<br />
H k [ H k Px<br />
H k + W ] H k P<br />
k k<br />
k<br />
xk<br />
= { P<br />
} H W<br />
From Eq.(6-23), the equation above becomes<br />
− 1 T −1<br />
−1<br />
T −1<br />
[ P′<br />
+ H W H ] H<br />
= W<br />
x k<br />
k<br />
k<br />
k<br />
k<br />
k<br />
k<br />
k<br />
k<br />
k<br />
T<br />
k<br />
k<br />
k<br />
−1<br />
1<br />
]<br />
k<br />
k<br />
k<br />
k<br />
k<br />
k<br />
−1<br />
(6-27)<br />
(6-28)<br />
According to the relation (D and C should be positive definite)<br />
−1<br />
−1<br />
−1<br />
−1<br />
CB ( ACB + D)<br />
= ( C + BD A)<br />
BD<br />
(6-29)<br />
then Eq.(6-28) becomes<br />
T<br />
T<br />
= P′<br />
H ( H P′<br />
H + W )<br />
xk k k xk<br />
= P′<br />
H<br />
xk<br />
T<br />
k<br />
k<br />
−1<br />
T<br />
T −1<br />
−1<br />
T −1<br />
−1<br />
−1<br />
{ H k Px′<br />
H k + Rk<br />
I − Gk<br />
( Gk<br />
Rk<br />
Gk<br />
) Gk<br />
Rk<br />
] } = K k<br />
k<br />
[ (6-30)