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Manual de Aligeramiento de Estructuras - ConcretOnline

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Q= C arga por metro lineal.I = Intereje.S = Suma <strong>de</strong> la sobrecargas.C = Concarga.C s = Coeficiente <strong>de</strong> pon<strong>de</strong>ración <strong>de</strong> la sobrecarga.C c = Coeficiente <strong>de</strong> pon<strong>de</strong>ración <strong>de</strong> la concarga.s max = Q·l 2 /11s max = (647,37·5,4 2 ) /11 = 1716,119Adoptando un perfil IPE 140 la tensión es:s*= s max / Ws*= 171612 / 77.3 = 2.220 < s adm. = 2600 kg/cm 2M flector = Q·l 2 /8M flector = 464·5,4 2 / 11 = 1230,02s = 1230,02 / 77,3 = 15,91 kg/cm 2C álculo <strong>de</strong> la flechaf = 0415 [(s l 2 )/ h]f = 0,415 [(15,91·5,4 2 )/14] = 13,75 mm > L/400 = 13,5 mmNo cumple por flecha, se <strong>de</strong>berá probar con un perfil mayor.C álculo <strong>de</strong> la flecha con un perfil IPE-160.M flector = Q·l 2 /8M flector = 464·5,4 2 / 11 = 1230,02s = 1230,02 / 109 = 11,28 kg/cm 2f = 0415 [(s l 2 )/ h]f = 0,415 [(11,28·5,4 2 )/16] = 8,53 cm < L/400 = 13,5 cm• 2º caso con bovedilla cerámica.Pon<strong>de</strong>ración <strong>de</strong> cargasQ = I (S+C)Q = 0,7 (300 + 300) = 420 kg/mlQ = I [(S· Cs)+(C· Cc )]Q’ = 0,7 [(1,5·300)+(1,33·300)] =594,3 kg/mls max = Q·l 2 /11s max = (594,3·5,4 2 ) / 11 = 1575,43Adoptando un perfil IPE 140 la tensión es:s*= s max / Ws*= 157543 / 77.3 = 2038,07 < s adm. = 2600 kg/cm 2Mflector = Q·l2 /8Mflector = 420·5,4 2 / 11 = 1114,70s = 1114,70 / 77.3 = 14,42 kg/cm 2C álculo <strong>de</strong> la flechaf = 0415 [(s l 2 )/ h]f = 0,415 [(14,42·5,4 2 )/14] = 12,46 mm < L/400 = 13,5 mm<strong>Manual</strong> <strong>de</strong> <strong>Aligeramiento</strong> <strong>de</strong> <strong>Estructuras</strong>73

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