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8.4 Properties of the Determinant 191<br />

Definition For M = (m i j) a square matrix, the adjoint matrix adj M is<br />

given by<br />

adj M = (cofactor(m i j)) T .<br />

Example 107<br />

⎛ ( ) 2 0<br />

det<br />

⎛ ⎞<br />

1 1<br />

3 −1 −1<br />

( )<br />

adj ⎝1 2 0⎠ =<br />

−1 −1<br />

− det<br />

0 1 1<br />

1 1<br />

⎜ ( )<br />

⎝ −1 −1<br />

det<br />

2 0<br />

( ) 1 0<br />

− det<br />

0 1<br />

( ) 3 −1<br />

det<br />

0 1<br />

( ) 3 −1<br />

− det<br />

1 0<br />

( ) ⎞<br />

1 2<br />

det<br />

0 1<br />

( )<br />

3 −1<br />

− det<br />

0 1<br />

( ) ⎟ 3 −1 ⎠<br />

det<br />

1 2<br />

T<br />

Reading homework: problem 6<br />

Let’s compute the product M adj M. For any matrix N, the i, j entry<br />

of MN is given by taking the dot product of the ith row of M and the jth<br />

column of N. Notice that the dot product of the ith row of M and the ith<br />

column of adj M is just the expansion by minors of det M in the ith row.<br />

Further, notice that the dot product of the ith row of M and the jth column<br />

of adj M with j ≠ i is the same as expanding M by minors, but with the<br />

jth row replaced by the ith row. Since the determinant of any matrix with<br />

a row repeated is zero, then these dot products are zero as well.<br />

We know that the i, j entry of the product of two matrices is the dot<br />

product of the ith row of the first by the jth column of the second. Then:<br />

M adj M = (det M)I<br />

Thus, when det M ≠ 0, the adjoint gives an explicit formula for M −1 .<br />

Theorem 8.4.2. For M a square matrix with det M ≠ 0 (equivalently, if M<br />

is invertible), then<br />

M −1 = 1<br />

det M adj M<br />

The Adjoint Matrix<br />

191

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