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Bio-medical Ontologies Maintenance and Change Management

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198 I.R. Godínez et al.<br />

RECALLING PHASE<br />

STEP 1:<br />

A pattern xω , that could be or not from the fundamental set, is presented<br />

to each Vl , l =1, 2,...,q. First, we have to apply the vector partition operator<br />

to xω :<br />

ρ(x ω ,q)= � x ω1 , x ω2 , ..., x ωq�<br />

then for each Vl matrix <strong>and</strong> xωl partition with l = {1, 2, ..., q}, theΔβ<br />

operation is done <strong>and</strong> the resulting vector is assigned to a vector called zωl :<br />

zωl = VlΔβxωl .Thei−th component of the resulting vector is given as:<br />

z ωl<br />

i =<br />

n�<br />

j=1<br />

β(V l ij,x ωl<br />

j )<br />

STEP 2:<br />

It is necessary to build the max sum vector s according to the definition<br />

1, in order to obtain the corresponding zint ϖl given as:<br />

zint ωl<br />

i =<br />

� 1ifsi = �<br />

k∈θ<br />

0 otherwise<br />

sk ∧ zint ωl<br />

i =1<br />

where θ = � i|zint ωl<br />

i =1� .<br />

STEP 3:<br />

An intermediate vector I is created. This vector will contain the sum of<br />

the i−th components of the zint ϖl vectors:<br />

I ϖ i =<br />

q�<br />

l=0<br />

zint ϖl<br />

i<br />

then the corresponding yϖ vector is obtained by:<br />

y ϖ i =<br />

⎧<br />

⎨<br />

1 I<br />

⎩<br />

ϖ i = p �<br />

I<br />

k=1<br />

ω k<br />

0 otherwise<br />

3.2.2 Alpha-Beta Heteroassociative Multimemories of Type Min<br />

LEARNING PHASE<br />

Let A = {0, 1} ,n,p ∈ Z + ,μ ∈{1, 2, ...p} ,i ∈{1, 2, ..., p} <strong>and</strong> j ∈{1, 2, ...n}<br />

<strong>and</strong> let be x ∈ A n <strong>and</strong> y ∈ A p input <strong>and</strong> output vectors, respectively. The<br />

corresponding fundamental set is denoted by {(x μ , y μ ) | μ =1, 2, ..., p}.<br />

The fundamental set must be built according to the following rules. First,<br />

the y vectors are built with the zero-hot codification. Second, to each y μ<br />

vector correspond one <strong>and</strong> only one x μ vector, this is, there is only one<br />

couple (x μ , y μ ) in the fundamental set.<br />

(2)

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