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color into the appropriate RGB color or vise versa, post multiply by the c<strong>on</strong>versi<strong>on</strong><br />

matrix M or its inverse:<br />

74<br />

[RGB] =[XY Z][M] (3.6)<br />

[XY Z]=[RGB][M] −1<br />

(3.7)<br />

However, the resulting RGB color from the transformati<strong>on</strong> may be invalid if<br />

the color is not within the gamut of colors supported by the RGB primaries. There<br />

are two types of out-of-gamut colors: those that have a chromaticity that cannot<br />

be matched by the primaries <strong>and</strong> those that experience luminance overflow. The<br />

first set of colors, when mapped to a set of primary phosphors, gives RGB values<br />

of less than zero. The sec<strong>on</strong>d set, yields RGB values greater than <strong>on</strong>e, as the<br />

magnitude of the color in <strong>on</strong>e or more channels may greater than the maximum<br />

luminance of the display.<br />

The problem of displaying such out-of-gamut colors is an important issue for<br />

painting, since many comm<strong>on</strong>ly used real-world pigments fall outside the gamut<br />

of existing color m<strong>on</strong>itors.<br />

Most gamut-matching methods seem to fall into two general categories: global<br />

<strong>and</strong> local approaches. A local approach examines each pixel, or color, in an image<br />

individually <strong>and</strong> adjusts <strong>on</strong>ly those that are out of gamut. A global approach<br />

applies informati<strong>on</strong> gathered from the entire image when c<strong>on</strong>sidering how to modify<br />

every pixel in the image, even those within the gamut.<br />

Figure 3.22 describes an example of a visible color Q which is unable to be<br />

realized by the RGB primaries. The chromaticity diagram makes it im<strong>media</strong>tely<br />

clear why mixtures of three visible light sources can never reproduce all visible<br />

colors. It is geometrically impossible for a triangle inscribed within the spectral<br />

locus to simultaneously circumscribe it. In this case, we have: Q − Rˆr = Gˆg + B ˆ b.

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