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PHYS08200604017 Manimala Mitra - Homi Bhabha National Institute

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where Λ is the cut-off scale of the theory and the underline sign in the superscript represents<br />

the particular S 3 representation from the tensor product of the two S 3 doublets 1 .<br />

Since (D l D l ) andξ∆are2×2 productswhich couldgiveeither 1or2, andsince wecanobtain<br />

1 either by 1×1 or 2×2, we have two terms coming from (D l D l ξ∆). The (D l D l )(ξ∆)<br />

as 1 ′ ×1 ′ term does not contribute to the neutrino mass matrix. In this model the presence<br />

of the Z 4 symmetry prevents the appearance of the usual 5 dimensional D l D l HH<br />

and l 1 l 1 HH Majorana mass term for the neutrinos. In fact, the neutrino mass matrix is<br />

completely independent of H due to the Z 4 symmetry. In addition, there are no Yukawa<br />

couplings involving the neutrinos and the flavon φ e due to Z 4 or/and Z 3 symmetry. The<br />

S 3 symmetry is broken spontaneously when the flavon ξ acquires a vacuum VEV:<br />

( )<br />

u1<br />

〈ξ〉 = . (6.8)<br />

u 2<br />

TheSU(2) L<br />

×U Y (1)breaksattheelectroweak scalebytheVEVoftheSU(2)doublet<br />

Higgs H. The VEV of the Higgs triplet is<br />

( ) ( )<br />

〈∆1 〉<br />

0 0<br />

〈∆〉 = , where 〈∆<br />

〈∆ 2 〉<br />

i 〉 = . (6.9)<br />

v i 0<br />

The neutrino get masses due to the VEV of the Higgs triplet field ∆ and as well as the<br />

standard model gauge singlet field ξ. The mass matrix of the neutrino is given as<br />

⎛<br />

⎞<br />

w<br />

2y 4 2y<br />

Λ 3 v 2 2y 3 v 1<br />

m ν = ⎝ u<br />

2y 3 v 2 2y 2 v 2 w<br />

1 2y<br />

Λ 2<br />

⎠ , (6.10)<br />

Λ<br />

w u<br />

2y 3 v 1 2y 2 2y 1 v 1<br />

Λ 1 Λ<br />

where w = u 1 v 2 +u 2 v 1 . For the VEV alignments<br />

the neutrino mass matrix reduces to the form<br />

⎛<br />

2u<br />

2y 1 v 1 4 2y<br />

Λ 3 v 1 2y 3 v 1<br />

m ν = ⎝ u<br />

2y 3 v 1 2y 1 v 1 2u<br />

1 2y 1 v 1<br />

Λ 2 Λ<br />

2u<br />

2y 3 v 1 2y 1 v 1 u<br />

2 2y 1 v 1<br />

Λ 1 Λ<br />

v 1 = v 2 , and u 1 = u 2 , (6.11)<br />

⎞<br />

⎠ . (6.12)<br />

We discuss about the VEV alignments in section 6.4. Denoting u 1<br />

Λ<br />

as u ′ 1 the mass matrix<br />

becomes<br />

⎛ ⎞<br />

2y 4 u ′ 1 y 3 y 3<br />

m ν = 2v 1<br />

⎝ y 3 y 1 u ′ 1 2y 2 u ′ ⎠<br />

1 , (6.13)<br />

y 3 2y 2 u ′ 1 y 1 u ′ 1<br />

1 The term (l l D l ∆) denotes (l T l Ciτ 2D l ∆), where C is the charge conjugation operator.<br />

146

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