PHYS08200604017 Manimala Mitra - Homi Bhabha National Institute
PHYS08200604017 Manimala Mitra - Homi Bhabha National Institute
PHYS08200604017 Manimala Mitra - Homi Bhabha National Institute
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where Λ is the cut-off scale of the theory and the underline sign in the superscript represents<br />
the particular S 3 representation from the tensor product of the two S 3 doublets 1 .<br />
Since (D l D l ) andξ∆are2×2 productswhich couldgiveeither 1or2, andsince wecanobtain<br />
1 either by 1×1 or 2×2, we have two terms coming from (D l D l ξ∆). The (D l D l )(ξ∆)<br />
as 1 ′ ×1 ′ term does not contribute to the neutrino mass matrix. In this model the presence<br />
of the Z 4 symmetry prevents the appearance of the usual 5 dimensional D l D l HH<br />
and l 1 l 1 HH Majorana mass term for the neutrinos. In fact, the neutrino mass matrix is<br />
completely independent of H due to the Z 4 symmetry. In addition, there are no Yukawa<br />
couplings involving the neutrinos and the flavon φ e due to Z 4 or/and Z 3 symmetry. The<br />
S 3 symmetry is broken spontaneously when the flavon ξ acquires a vacuum VEV:<br />
( )<br />
u1<br />
〈ξ〉 = . (6.8)<br />
u 2<br />
TheSU(2) L<br />
×U Y (1)breaksattheelectroweak scalebytheVEVoftheSU(2)doublet<br />
Higgs H. The VEV of the Higgs triplet is<br />
( ) ( )<br />
〈∆1 〉<br />
0 0<br />
〈∆〉 = , where 〈∆<br />
〈∆ 2 〉<br />
i 〉 = . (6.9)<br />
v i 0<br />
The neutrino get masses due to the VEV of the Higgs triplet field ∆ and as well as the<br />
standard model gauge singlet field ξ. The mass matrix of the neutrino is given as<br />
⎛<br />
⎞<br />
w<br />
2y 4 2y<br />
Λ 3 v 2 2y 3 v 1<br />
m ν = ⎝ u<br />
2y 3 v 2 2y 2 v 2 w<br />
1 2y<br />
Λ 2<br />
⎠ , (6.10)<br />
Λ<br />
w u<br />
2y 3 v 1 2y 2 2y 1 v 1<br />
Λ 1 Λ<br />
where w = u 1 v 2 +u 2 v 1 . For the VEV alignments<br />
the neutrino mass matrix reduces to the form<br />
⎛<br />
2u<br />
2y 1 v 1 4 2y<br />
Λ 3 v 1 2y 3 v 1<br />
m ν = ⎝ u<br />
2y 3 v 1 2y 1 v 1 2u<br />
1 2y 1 v 1<br />
Λ 2 Λ<br />
2u<br />
2y 3 v 1 2y 1 v 1 u<br />
2 2y 1 v 1<br />
Λ 1 Λ<br />
v 1 = v 2 , and u 1 = u 2 , (6.11)<br />
⎞<br />
⎠ . (6.12)<br />
We discuss about the VEV alignments in section 6.4. Denoting u 1<br />
Λ<br />
as u ′ 1 the mass matrix<br />
becomes<br />
⎛ ⎞<br />
2y 4 u ′ 1 y 3 y 3<br />
m ν = 2v 1<br />
⎝ y 3 y 1 u ′ 1 2y 2 u ′ ⎠<br />
1 , (6.13)<br />
y 3 2y 2 u ′ 1 y 1 u ′ 1<br />
1 The term (l l D l ∆) denotes (l T l Ciτ 2D l ∆), where C is the charge conjugation operator.<br />
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