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PHYS08200604017 Manimala Mitra - Homi Bhabha National Institute

PHYS08200604017 Manimala Mitra - Homi Bhabha National Institute

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The group contains two one-dimensional and one two-dimensional irreducible representations.<br />

The one-dimensional representations are given by [37]<br />

The two-dimensional representation is given by<br />

(<br />

0 1<br />

2 : S =<br />

1 0<br />

1 : S = 1, T = 1 (2.47)<br />

1 ′ : S = −1, T = 1 . (2.48)<br />

)<br />

, T =<br />

( )<br />

ω 0<br />

0 ω 2<br />

. (2.49)<br />

The character table is given in Table 2.2. Using the Table we can write down the rules<br />

for the tensor products. For the one-dimensional irreducible representations we have<br />

1×1 = 1, 1×1 ′ = 1 ′ , 1 ′ ×1 ′ = 1 . (2.50)<br />

Tensor products between two doublets ψ = (ψ 1 ,ψ 2 ) T and φ = (φ 1 ,φ 2 ) T are given as<br />

where<br />

2×2 = 1+1 ′ +2 , (2.51)<br />

1 ≡ ψ 1 φ 2 +ψ 2 φ 1 , (2.52)<br />

1 ′ ≡ ψ 1 φ 2 −ψ 2 φ 1 , (2.53)<br />

( )<br />

ψ2 φ<br />

2 ≡ 2<br />

. (2.54)<br />

ψ 1 φ 1<br />

The complex conjugate doublet ψ ⋆ is given as 2 ⋆ for which the generators are S ⋆ and T ⋆ .<br />

One can easily check that ψ ⋆ does not transform as doublet (2) of S 3 and therefore for<br />

this case a meaningful way of writing the tensor products for the conjugate fields is by<br />

defining<br />

( )<br />

ψ<br />

ψ ′ ≡ σ 1 ψ ⋆ ⋆<br />

= 2<br />

ψ1<br />

⋆ . (2.55)<br />

Using the relations σ 1 S ⋆ σ 1 = S and σ 1 T ⋆ σ 1 = T one can show that ψ ′ transforms as a<br />

doublet. Then the tensor products ψ ′ ×φ are given by Eq. (2.51) where<br />

1 ≡ ψ ⋆ 1φ 1 +ψ ⋆ 2φ 2 , (2.56)<br />

1 ′ ≡ ψ2φ ⋆ 2 −ψ1φ ⋆ 1 , (2.57)<br />

( )<br />

ψ<br />

⋆<br />

2 ≡ 1 φ 2<br />

ψ2φ ⋆ . (2.58)<br />

1<br />

28

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