Mathcad - ee217projtodonew2.mcd

Solve
r . b i . bn Z . e β β . V . s Z e Z . S i . bn Z . e β i . bn Z . π Z S i . bn Z . π r b Z . π V s Z . S i . cn Z e V . s Z e r . b i . cn Z e
Z S r b g . m Z . π Z e Z e Z π
Z . L
Z . S i . bn Z . π g m r . b i . bn Z . π g m Z . π V . s g m i . bn Z . π Z . e g m Z . S i cn r . b i cn i . cn Z e i . cn Z π
Z S r b g . m Z . π Z e Z e Z π
A v
Z . e
i . cn Z π r . b i cn i . bn Z π Z . S i . bn Z . π g m r . b i . bn Z . π g m Z . π V . s g m Z . S i cn V s
β N, I C , s . para R L N, I C , s , Z L N, I C , s
r b ( N) β N, I C , s 1 . Z e ( N,
s)
Z π N, I C , s
Z S r b g . m Z . π Z e Z e Z π
A v = 2.845 5.479i Zero Source Impedance
Voltage Gain
A i β N, I C , s . para R L N, I C , s , Z L N, I C , s A i = 1.438 2.475i kΩ Infinite Source Impedance
Current Gain
Now we can use the gains we just calculated to find the equivalent input voltage and current
sources and the correlation between the two. In order to find the equivalent input noise source,
we must first know the magnitude of each of the individual noise sources. These are well known
values of 4kTr b for the base resistance thermal noise, 2qI B for the base current shot noise, and
2qI C for the collector current shot noise.
v bn ( N ) 4. k. Temp. r b ( N)
v bn N = Base Thermal Noise Voltage
( ) 0.271 nV Hz
i cn I C
i bn I C
2q . . I C
2q .
I
. C
β 0
i cn I C = 56.604 pA Collector Shot Noise Current
Hz
i bn I C = 4.682 pA Base Shot Noise Current
Hz
i biasn R bias
i RLn R L
4k . . 1
Temp. i biasn R bias 2.126 pA
R bias
Hz
4k . . 1
Temp. i RLn R L 4.626 pA
R L N, I C , s
Hz
= Bias Resistor Current Noise
= Load Resistor Current Noise