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FIELD TESTING AND EVALUATION OF DUST DEPOSITION AND ...

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volume, and dm ceil /dt is the mass per unit time passing through the ceiling of the control<br />

volume Because the road dust is usually the overwhelming source of dust, that is,<br />

dm road /dt >> dm ambin /dt + dm ceil /dt , the horizontal flux dm out /dt for these conditions is<br />

approximately:<br />

dm road /dt = dm out /dt<br />

which is the horizontal mass flux of dust from the road.<br />

Equation 4-19<br />

4.1.3.1b Deposition at the floor and vertical flux of dust through the ceiling of the<br />

control volume downwind of the road<br />

The total loss of material diffusing vertically through the ceiling and depositing<br />

on the floor of the control volume to the left of the road may be calculated by first<br />

calculating the effective concentration at position x to the left of x 0 (i.e., the left edge of<br />

the road). We use the equation:<br />

V<br />

dC(<br />

x)<br />

dx<br />

=<br />

− C(<br />

x)[<br />

V<br />

∆z<br />

d<br />

+ K]<br />

Equation 4-20<br />

where, V is the wind speed that carries the dust through the control volume (CV),<br />

C(x) is the concentration of dust mass at position x in the CV,<br />

x is the horizontal position in the CV, increasing to the left,<br />

z is the vertical position in the CV, increasing from the floor to the ceiling,<br />

V d is the deposition velocity, and<br />

K is a coefficient having the dimensions of velocity.<br />

A solution to Equation 4-20 is:<br />

dmroad<br />

= Vd<br />

+ K<br />

C(<br />

x)<br />

dt<br />

exp−<br />

x − x<br />

V∆z∆L<br />

V∆z<br />

o<br />

[ ] ( )<br />

<br />

Equation 4-21<br />

Multiplying C(x) by V d L (i.e., the deposition velocity times the unit length of the road)<br />

and integrating with respect to x from x = x 0 to x = gives:<br />

dm<br />

depos<br />

dt<br />

V<br />

=<br />

d<br />

dm<br />

dt<br />

( V + K )<br />

d<br />

road<br />

Equation 4-22<br />

4-8

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