July-August - Air Defense Artillery School
July-August - Air Defense Artillery School
July-August - Air Defense Artillery School
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."T-P------------"'l:::)ruTTL..,\~l~J. ,~v-:-rl ~h"1t\ .. Lr-":)"H=vUrT11---pt''RKTUTIti~L-,l::.r;-;1:rl\ lr-.;;:::,;---------------:4r,(~<br />
The formula for the lateral correction is:<br />
51<br />
dA=---<br />
COS £1<br />
T)pical example<br />
To illustrate the use of the aboye method, consider the<br />
oIlowingtrial shot problem for a 3 inch battery using ~ 142<br />
hell and ~ 143A3 fuze. The pertinent trial shot data reuired<br />
for the solution of the problem by this method is<br />
" follows:<br />
~ison the right<br />
1= 5000 yards<br />
l = 5000 )'ards<br />
L = 1207 mils<br />
£1 = 800 mils<br />
f:! = 966 mils<br />
Assumed i\ IV<br />
= 2850 ftlsec<br />
Average observed deviations<br />
From 01: Above 7 mils<br />
From 01: Left 8 mils<br />
(Slant plane)<br />
From 0:: Short 20 mils<br />
(Slant plane)<br />
The solution of this problem by this method is as follows:<br />
Cl = 3.03 (See table II)<br />
3.03 _<br />
C~ = 0.707 X 2.46 = 1.7)<br />
3.03<br />
C3 = 0.812 X .926 = 4.03<br />
TABLE I<br />
Then .6i\I\' = T (3.03) (7) + (1.75) (8)<br />
(4.03) (20) = J- 21 T 14 - 81 = -46 feet per<br />
second<br />
The developed muzzle velocity is then 2850 - 46 =<br />
2804 feet per second<br />
The vertical correction required to bring the shots to<br />
the !\IV line is - 8 - 46 (.03) or down 8 mils<br />
The lateral correction required to mm'e the bursts into<br />
8<br />
the plane of the target is 0 -0- or right II mils .<br />
.I I<br />
Derivation of formulas<br />
Cl FACTORSFon 901\11\1AA GUN<br />
HE SHELL M71, FUZE M43A3<br />
The key to the above method of solution lies in a complete<br />
understanding of the d%H factor for ballistic corrections<br />
as given in the graphical firing tables. Referring to<br />
figure I, the trial shot point is at T and the burst at B. The<br />
line BK is drawn at right angles to the line of position. The<br />
length of the line PK in altitude or the length of the line TP<br />
in range determine the length of the line TM or the muzzle<br />
velocity correction. If the muzzle velocitv deviation TM<br />
was 100 feet per second the length of the line PK would be<br />
(d%H factor) (H) and for a muzzle velOCitydeviation of<br />
I foot per second, the length of the line PK would be<br />
H<br />
(d%H factor) 100. Likewise the length of the line TP for<br />
10000 8.77 6.58 5.26<br />
9000 12.I 5 8. I I 6.08 4.88 4.06 3.48<br />
8000 11.10 7.42 5.55 4.46 3.70 3.18 2.86<br />
.!:<br />
... '"<br />
>.:<br />
7000<br />
6000<br />
5000<br />
17.10<br />
14.30<br />
9.72<br />
8.55<br />
7.15<br />
6.49<br />
5.72<br />
4.77<br />
4.88<br />
4.28<br />
3.57<br />
3.89<br />
3.43<br />
2.94<br />
3.34<br />
2.94<br />
2.45<br />
2.94<br />
2.59<br />
2.17<br />
2.65<br />
2.34<br />
1.96<br />
2.43<br />
2.15<br />
1.79<br />
2.00<br />
1.67<br />
.- 4000 11.42 5.71 3.81 2.94 2.42 2.02 1.79 1.62 1.48 1.38 1.30<br />
:..><br />
-g 3000 8.58 4.29 2.94 2.27 1.88 1.57 1.38 1.25 1.15 1.07 1.01<br />
-= 2000 2.94 2.02 1.56 1.25 1.07 0.95 0.86 0.79 0.74 0.70<br />
< 1000 I.Il 0.83 0.67<br />
8000<br />
7000<br />
~ 6000<br />
" 5000 13.50<br />
r 4000 10.52<br />
~ 3000<br />
2000<br />
'- 1000<br />
-=<br />
-:::::<br />
1000 2000 3000 4000 5000 6000 7000 8000 9000 10000 IlOOO<br />
1000<br />
11.42<br />
10.00<br />
8.35<br />
6.75<br />
5.40<br />
4.05<br />
2000<br />
Horizontal Range in Yards<br />
TABLEII<br />
Cl FACTORSFOR3 INCHAA GUN<br />
HE SHELL :M42, FUZE M43<br />
7.62 5.88<br />
6.67 5.15 4.24 3.77<br />
5.72 4.42 3.64 3.24 2.86<br />
4.63 3.58 3.03 2.69 2.38 2.24<br />
3.70 2.78 2.35 2.08 1.91 1.79 1.71<br />
2,78 2.08 1.77 1.57 1.43 1.34 1.28<br />
1.80 1.39 I.l4 1.01 0.96 0.93 0.89<br />
0.69 0.57 0.50 0.48<br />
3000 4000 5000 6000 7000 8000 9000<br />
Horizontal Range in Yards